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Feliz [49]
3 years ago
13

Find the value of x.

Mathematics
2 answers:
miskamm [114]3 years ago
8 0
88 is x i think lololol
dusya [7]3 years ago
6 0

Answer:

66

Step-by-step explanation:

For quadileraterals, the angles are always supposed to add up to 360 so first you add all of the angles that you know (103 +133+ 58=  294) and then subtract that number by 360.

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Kevin plans to put concrete on a rectangular portion of his driveway. The portion is 10 feet long and 3 inches high. The price o
Mashutka [201]
3 feet wide hope it helps
8 0
3 years ago
Read 2 more answers
At the beginning of an experiment, the number of bacteria in a colony was counted at time t=O. The number of bacteria in the col
yan [13]

Answer:

1092

Step-by-step explanation:

We have been given that the number of bacteria in the colony t minutes after the initial count modeled by the function B(t)=9(3)^t. We are asked to find the average rate of change in the number of bacteria over the first 6 minutes of the experiment.

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

Upon substituting our given values, we will get:

\text{Average rate of change}=\frac{b(6)-b(0)}{6-0}

\text{Average rate of change}=\frac{9(3)^6-9(3)^0}{6}

\text{Average rate of change}=\frac{9(729)-9(1)}{6}

\text{Average rate of change}=\frac{6561-9}{6}

\text{Average rate of change}=\frac{6552}{6}

\text{Average rate of change}=1092

Therefore, the average rate of change in the number of bacteria is 1092 bacteria per minute.

8 0
3 years ago
WRITE your SOLUTION: Alivia has 42 apps on her phone, and she buys 3
MaRussiya [10]

Answer:

in 6 weeks

Step-by-step explanation:

If you graph 42+3x and 24+6x they will intersect at 6

8 0
3 years ago
After grooming a dog, Anita likes to give it treats. She gives each dog the same number of treats. There are 210 treats in a box
Luba_88 [7]

Answer:15 each. that's a lot.

2 boxes of treats is 420 treats

420 treats / 28 dogs is also 15 treats per dog

Step-by-step explanation:

7 0
3 years ago
Multiplication in GF(24 ): Compute A(x)B(x) mod P(x) in GF(24 ) using the irreducible polynomial P(x) = x 4 + x + 1, where A(x)
tankabanditka [31]

Answer:

Step-by-step explanation:

hello,

i advice you check the question again if it is GF(2^{4}) or GF(24). i believe the question should rather be in this form;

multiplication in GF(2^{4}): Compute A(x)B(x) mod P(x) = x^{4} + x+1, where A(x)=x^{2}+1, and B(x)=x^{3} + x+1.

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)=(x^{2} +1) (x^{3}+x+1) mod (x^{4}+x+1  ) = (x^{5} +x^{3}+x^{2}  ) + (x^{3}+x+1  ) mod (x^{4} + x+1 )

= x^{5}+2x^{3} +x^{2}  + x + 1 mod(x^{4}+x+1  )

=2x^{2} +1

please note that the division by the modulus above we used

\frac{x^{5}+2x^{3}+x^{2} +1  }{x^{4}+x+1}= x+\frac{2x^{3} +1}{x^{4}+x+1}

5 0
3 years ago
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