Question

In figure AB and CD bisect each other at O. State the 3 pairs of equal parts in ∆AOC and ∆BOD. Is ∆AOC ≅ ∆BOD? Give reasons

Answer 1

Answer:

SEE EXPLANATION

Step-by-step explanation:

$In\:\triangle AOC \:\&\:\triangle BOD$

$AO \cong OB.... (given)$

$\angle AOC \cong\angle BOD$

$(vertical \: \angle s)$

$CO \cong OD.... (given)$

$\therefore \triangle AOC \:\cong\:\triangle BOD$

$(SAS \: postulate)$

So, the 3 pairs of equal parts in ∆AOC and ∆BOD are:

$AC = BD$

$m\angle OAC = m\angle OBD$

$m\angle OCA = m\angle ODB$