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3 years ago

12

0.15 x 0.60 = 0.09 show the formula in doing it

1 answer:

Alexxx [7]3 years ago

7 0

Answer: x=1

Step-by-step explanation:

0.15 x 0.60 = 0.09

0.15 x 0.60 x 100= 0.09 x 100

9x = 9

9x/9= 9/9

x=1

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A teacher is buying pencils for her classroom. If a dozen pencils cost $0.97, how many pencils can she purchase with $5?

mixas84 [53]

Answer:

The teacher can purchase 61 pencils with $5

Step-by-step explanation:

This is a simple proportion problem. It can be solved by pure logic reasoning without any formulas

It a dozen pencils cost $0.97, each pencil cost $0.97/12=0.08083

With $5 she will be able to purchase 5/0.08083=61.85 pencils

We must round to the nearest lower integer

The teacher can purchase 61 pencils with $5

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3 years ago

A secret code is made up of three digits followed by

kari74 [83]

Most likely 10 because the initial amount is 5

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3 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

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lidiya [134]

Answer:

54.609 < 54.69

Step-by-step explanation:

54.69 is closer to a whole number than 54.609 making it the greater number

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3 years ago

The circumference of a circle is10π feet what is the radius

sweet-ann [11.9K]

Answer:

r = 5 ft

Step-by-step explanation:

The circumference of a circle is given by

C = 2*pi*r

We are given the circumference

10 *pi = 2 * pi *r

Divide each side by 2 *pi

10 pi/ 2 pi = 2*pi*r/2pi

5 =r

8 0

3 years ago