Ax²+bx+c=0
The formula to solve for x is:

So for 3x²+13x+10=0, plug in the data
x=-13±√13²-4(3)(10) / 2(3)
x=-13±√169-120 / 6
x=-13±√49 /6
x=-13<span>±7 / 6
x=-13+7/6
x=-6/6
x=-1x=-13-7/ 6
x=-20/6 or 3.3repeating
3x</span>²+14x+15=0
x=-14±√14²-4(3)(15) / 2(3)
x=-14±√196-180 /6
x=-14<span>±</span>√16 / 6
x=-14+4/6
x=-10/6 or 1.6repeatingx=-14-4/6
x=-18/6
x=-3
16(4) = 64. 7(3) = 21
64/21 simplifies to 3 and 1/21 as 21 goes into 64 three times. Option C is your answer.
I hope this helps good luck
Answer:
D. f(x) = -6x^3 -5x^2 +21x
Step-by-step explanation:
The given zeros mean the function has factors ...
(x -(-7/3))(x -3/2)(x -0)
Multiplying by 6, we can write this as ...
(3x +7)(2x -3)(x) = 6x^3 +5x^2 -21x
And multiplying by -1 gives ...
-6x^3 -5x^2 +21x . . . . . matches choice D
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<em>Additional comment</em>
The product of factors will be zero when f(x) = 0. This means we can multiply or divide by any convenient factor and the product will remain zero. Effectively, we have multiplied our original factorization by -6 to make the expression match one of the given forms. When we write this final expression as the function f(x), it remains true that the given zeros are zeros (x-intercepts) of f(x).