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mezya [45]
2 years ago
13

Which has a mass of about 10 kilograms? Watermelon Pencil Car Apple

Mathematics
2 answers:
Zolol [24]2 years ago
8 0

Answer:

watermelon ..........................................

scoundrel [369]2 years ago
4 0

Answer: watermelon

Step-by-step explanation:

they usually weigh 9-11kg

an apple or pencil is less than 10kg, and a car is way more than 10kg

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Which set of lengths are the side lengths of a right triangle? (9,15,17) (14,23,25) (20,30,40) (15,36,39)
goldfiish [28.3K]

Answer:

(15, 36, 39)

Step-by-step explanation:

Using pythagoreas formula: A^2 * B^2 = C^2

so a=15, b=36, c=39

15^2+36^2=39^2

6 0
3 years ago
But whats the answer
Gekata [30.6K]

Question: Mia and Kai want to rent a canoe at the boathouse on the river. It costs $6.95 to rent a canoe for 1 hour. The price per hour stays the same for up to 3 hours of rental. After 3 hours, the cost decreases to $4.50 per hour. How much would it cost Mia and Kai to rent a canoe for 4 hours?

Answer:

$23.30

Step-by-step explanation:

To do this I did 6.45(3) + 6.45-4.50

20. 85 + 2.45

23.30

Hope this helps ya!

5 0
2 years ago
Read 2 more answers
Help please thanks don’t know how to do this
Setler79 [48]

Answer:

a = 11.71 ; b = 15.56

Step-by-step explanation:

For this problem, we need two things.  The law of sines, and the sum of the interior angles of a triangle.

The law of sines is simply:

sin(A)/a = sin(B)/b = sin(C)/c

And the sum of interior angles of a triangle is 180.

45 + 110 + <C = 180

<C = 25

We can find the sides by simply applying the law of sines.

length b

7/sin(25) = b/sin(110)

b = 7sin(110)/sin(25)

b = 15.56

length a

7/sin(25) = a/sin(45)

a = 7sin(45)/sin(25)

a = 11.71

6 0
3 years ago
This is due in 2 minutes
larisa [96]
Stop with the links don’t work
5 0
3 years ago
Listen
ozzi

Answer:

scale factor = \frac{14}{5}

Step-by-step explanation:

The scale factor is the ratio of corresponding sides, image to original.

scale factor = \frac{7}{2.5} = \frac{7(2)}{2.5(2)} = \frac{14}{5}

4 0
3 years ago
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