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Aleks [24]
3 years ago
5

PLZ HELP ME ANSWER THIS I WILL GIVE BRAINLIEST!!!

Mathematics
1 answer:
marysya [2.9K]3 years ago
5 0

Answer:

They are the same answer in absolute value form and they are different because they are opposite numbers

Step-by-step explanation:

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Find the length of an arc of an 8" radius circle if the arc measures 45°. 2 in. 8 in. 16 in.
cricket20 [7]

Answer: 2π inches or 6.28 inches.

Step-by-step explanation:

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8 0
4 years ago
Plz help anybody will give branily
igomit [66]

#8. The answer would be 189. The LCM (least common multiple) of 2 or more numbers, is the multiple that each number has in common with one another. Here are the multiples of both numbers up to 189, to show 189 is the answer.

  • 21: 21, 42, 63, 84, 105, 126, 147, 168, 189
  • 27: 27, 54, 81, 108, 135, 162, 189

#9. The answer would be 41. Prime numbers are numbers that only have 2 favtors (1 and itself). Since 41 is only divisible by 1 and itself, without the answer being a decimal, it is a prime number.

#10. The answer would be 6. The GCF (greatest common factor) of 2 or more numbers, is the largest factor that each number has in common with one another. Here are the factors of both numbers, to show 6 is the answer.

  • 30: 1, 2, 3, 5, 6, 10, 15, 30.
  • 48: 1, 2, 3, 4, 6, 8, 12, 24, 48.

I hope this helps!

3 0
3 years ago
Helppp me plsssssssss<br><br>​
Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

  • \sf \:\:\:\:\:\:\:\:\:\:x_{k}=35
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k}=50
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42
  • \sf \:\:\:\:\:\:\:\:\:\:h=5

{\bf \:\: {By\:using\:the\: formula}} \\ \\

\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\

\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\

\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\

{\large{\frak{\pmb{\underline{Additional\: information }}}}}

MODE

  • Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

  • In a frequency distribution the class having maximum frequency is called the modal class.

{\bf{\underline{Formula\:for\: calculating\:mode:}}} \\

{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\

Where,

\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.

\small \blue{ \bigstar}\sf \: f_{k}=frequency\:of\:the\:modal\:class

\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class

\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class

\small \purple{ \bigstar}\sf \: h= width \:of\:the\:class\:interval

7 0
3 years ago
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