Answer:
a) 10.7 cm
b) 11.6 cm
c) 29.9 cm²
Step-by-step explanation:
a) sin(α)/a = sin(β)/b
sin(∠BCD)/BD = sin(DBC)/DC
sin(41°)/BD = sin(55°)/13.4
BD = 13.4*sin(41°)/sin(55°) = 10.73 cm ≈ 10.7 cm
b) From ΔBCD , ∠BDC = 180-(41+55) = 84°
∠ABD and ∠BDC are alternate interior angles, so they are congruent, and
∠ABD = ∠BDC = 84°
AD²= AB² + BD² - 2*AB*BD*cos (∠ABD) =
= 5.6² + 10.73² - 2*5.6*10.73*cos(84°) = 133.93 cm²
AD =√(133.93) ≈11.6 cm
c) Area(ADB) = (1/2)*AB*BD*sin(∠ABD)=(1/2)*5.6*10.73*sin(84°) ≈ 29.9 cm²
The problem is modelled as right angle triangle, shown in the diagram below
The distance between the pilot and the house is labelled as
Using the trigonometry ratio of sine
-19, -12, 1/2, 1, 5, 12 ----> least to greatest
12, 5, 1, 1/2, -12, -19 ----> greatest to least
Do the same as the last one, starting with the largest negative number, and ending with the largest positive number. The only difference in this case is that it is greatest to least. I tend to go from least to greatest first and then flip it around to get greatest to least (:
A. -1.3
B. 4.5
C. -5.4
D. 3.1
