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2 years ago

HURRYYY!!

Mathematics

2 answers:

MrMuchimi2 years ago

3 0

Answer:

The middle one

Step-by-step explanation:

lesya692 [45]2 years ago

3 0

7.31 x 10-2
is scientific notation

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EXPLAIN YOUR ANSWER NEED HELP ASAP

Dennis_Churaev [7]

The radius is half the diameter. 19*2=38. The diameter is 38.

7 0

2 years ago

Bobby catches 8 passes in 3 football games. At this rate how many passes dose he catch in 15 games?expine

stepan [7]

Answer: 40

Step-by-step explanation:

I can see the answer is 40, but let's try to figure out how to do it.

I like to use the rule of 3. Let's put the number of passes on the left side and the number of games on the right side.

$\frac{8}{x}=\frac{3}{15}$

''x'' represents the number of passes in 15 games.

Solve for x;

$x=\frac{15*8}{3}\\ x=\frac{120}{3}\\ x=40$

8 0

2 years ago

The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc

BaLLatris [955]

Answer:

$y(t)= 6-3cos(\dfrac{2\pi}{14}t )$

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

$y(t) = y_0+Acos(wt)$

The tide varies between 3ft and 9ft, which means its amplitude $A$ is

$A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}$

and its midline $y_0$ is

$y_o=3+3 \\\\\boxed{y_o= 6ft}$ .

Furthermore, since at $t=0$ the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is $-cos(\omega t)$ .

The period of the full cycle is 14 hours, which means

$\omega t =2\pi$

$\omega (t+14)= 4\pi$

giving us

$\boxed{\omega = \dfrac{2\pi}{14}.}$

With all of the values of the variables in place, the function modeling the situation now becomes

$\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}$

8 0

3 years ago

Correct answer gets brainliest or who ever answered first

timurjin [86]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

M(x)=−(x−5) 2 +25m, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 5, right parenthesis, squ

Aleksandr [31]

Answer:

Step-by-step explanation:

Given the function that represents the amount of mosquitoes as;

M(x) = -(x-5)² + 25

To get the maximum mosquitoes possible, we need to first find x;

At the maximum dM/dx = 0

dM//dx = -2(x-5)

0 = -2(x-5)

-2(x-5) = 0

-2x + 10 = 0

-2x = -10

x = 10/2

x = 5

Substitute x = 5 into the function;

M(5) = −(5−5)² +25

M(5) = 0+25

M(5) = 25

Hence the maximum number of mosquitoes is 25

8 0

2 years ago