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3 years ago

7

Sydney has been paying the minimum balance on her three credit cards each month. She has outlined the minimum payments for the n

ext four months. She decides to snowball her debt after Month 1 according to the interest rate instead of paying the minimum payment. Show the details of her payments for months 2 thru 4 using the snowball plan.

1 answer:

ipn [44]3 years ago

5 0

??? for 2 to 4 months

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mash [69]

Answer:

=> (xy)⁵z³

Step-by-step explanation:

hope it's helpful ..

4 0

3 years ago

Solve each equation.

ankoles [38]

Answer:

A. x=2

b. x=28/3 and in decimal it is x=9.3 and in fraction it is

x= 9 1/3

c. x=20

d. x=20/11 in decamal x=1.81 in fraction it is x=1 9/11

Step-by-step explanation:

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2 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

Line d is parallel to line c in the figure below. Parallel lines d and c are intersected by lines q and p to form 2 triangles. A

Verdich [7]

Answer:

A B C

Step-by-step explanation:

6 0

3 years ago

The binomial 8x+6 is equivalent to

andreyandreev [35.5K]

Using the Distributive Property

The answer would be 3.

2 *4x = 8x and 2 * 3 = 6, to get 8x 6

5 0

3 years ago

Read 2 more answers