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3 years ago

What is the area of the 50ft by 100ft yard?

Mathematics

2 answers:

zhuklara [117]3 years ago

6 0

5,000 sq ft
50 feet multiplying by 100 feet equal to 5,000 sq ft

mario62 [17]3 years ago

4 0

Answer: 4410 $ft^2$

Step-by-step explanation:

To find the area of a square or rectangle, all you need to do is multiply the length times the width:

L × W = A

The lengh is 100, and the width is 50

100 × 50 = 5000

However, in this problem, we also have other shapes in the rectangle. To find the area of JUST the green, we need to subtract the areas of the two circles and small blue rectangle.

First, let's get the two circles over with. To find the area of a circle, use this formula:

A = π $r^2$ r is the radius, which in this case, is 6

A = π $6^2$

A = 113 This isn't the exact answer, the exact answer would be 113.0973...

Now let's multiply the area of one of those circles by 2, since we have 2 circles:

113 × 2 = 226

Finally, we have to find the area of the blue rectangle. This is simple, just use the formula from the very beginning:

26 × 14 = 364

The last thing to do is to subtract the areas of the two circles and blue rectangle from the area of the entire thing:

5000 - (226 + 364) = 4410 $ft^2$

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Find the zeros of the following polynomial x^2-2x+1

muminat

If the polynomial is of the form x^2+bx+c (ie., no factor in front of the x^2!!) then you can look for numbers that add up to b and multiply to c.

So in this case: what two numbers, when added, give -2 and when multiplied, give 1? A little trial and error gives you -1 and -1.
So the factorization is (x-1)(x-1). This is zero for x=1. There is only one zero.

4 0

3 years ago

Read 2 more answers

A particular telephone number is used to receive both voice calls and fax messages. Suppose that 25% of the incoming calls invol

bagirrra123 [75]

Answer:

a) 0.214 = 21.4% probability that at most 4 of the calls involve a fax message

b) 0.118 = 11.8% probability that exactly 4 of the calls involve a fax message

c) 0.904 = 90.4% probability that at least 4 of the calls involve a fax message

d) 0.786 = 78.6% probability that more than 4 of the calls involve a fax message

Step-by-step explanation:

For each call, there are only two possible outcomes. Either it involves a fax message, or it does not. The probability of a call involving a fax message is independent of other calls. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

25% of the incoming calls involve fax messages

This means that $p = 0.25$

25 incoming calls.

This means that $n = 25$

a. What is the probability that at most 4 of the calls involve a fax message?

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$ .

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.25)^{0}.(0.75)^{25} = 0.001$

$P(X = 1) = C_{25,1}.(0.25)^{1}.(0.75)^{24} = 0.006$

$P(X = 2) = C_{25,2}.(0.25)^{2}.(0.75)^{23} = 0.025$

$P(X = 3) = C_{25,3}.(0.25)^{3}.(0.75)^{22} = 0.064$

$P(X = 4) = C_{25,4}.(0.25)^{4}.(0.75)^{21} = 0.118$

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.001 + 0.006 + 0.025 + 0.064 + 0.118 = 0.214$

0.214 = 21.4% probability that at most 4 of the calls involve a fax message

b. What is the probability that exactly 4 of the calls involve a fax message?

$P(X = 4) = C_{25,4}.(0.25)^{4}.(0.75)^{21} = 0.118$

0.118 = 11.8% probability that exactly 4 of the calls involve a fax message.

c. What is the probability that at least 4 of the calls involve a fax message?

Either less than 4 calls involve fax messages, or at least 4 do. The sum of the probabilities of these events is 1. So

$P(X < 4) + P(X \geq 4) = 1$

We want $P(X \geq 4)$ . Then

$P(X \geq 4) = 1 - P(X < 4)$

In which

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.25)^{0}.(0.75)^{25} = 0.001$

$P(X = 1) = C_{25,1}.(0.25)^{1}.(0.75)^{24} = 0.006$

$P(X = 2) = C_{25,2}.(0.25)^{2}.(0.75)^{23} = 0.025$

$P(X = 3) = C_{25,3}.(0.25)^{3}.(0.75)^{22} = 0.064$

$P(X$

$P(X \geq 4) = 1 - P(X < 4) = 1 - 0.096 = 0.904$

0.904 = 90.4% probability that at least 4 of the calls involve a fax message.

d. What is the probability that more than 4 of the calls involve a fax message?

Very similar to c.

$P(X \leq 4) + P(X > 4) = 1$

From a), $P(X \leq 4) = 0.214)$

Then

$P(X > 4) = 1 - 0.214 = 0.786$

0.786 = 78.6% probability that more than 4 of the calls involve a fax message

8 0

3 years ago

I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT

tatiyna

The first one is correct

5 0

3 years ago

Write an equation of the line in slope-intercept form that passes through (-3,5) and is perpendicular to y = -3x- 1

inna [77]

9514 1404 393

Answer:

y = 1/3x +6

Step-by-step explanation:

The slope of the given line is the coefficient of x, -3. The slope of the perpendicular line will be the opposite reciprocal of that:

-1/(-3) = 1/3

The point-slope equation is then ...

y -k = m(x -h) . . . . . for line of slope m through point (h, k)

Here, we have m = 1/3, (h, k) = (-3, 5), so the point-slope equation is ...

y -5 = 1/3(x +3)

y = 1/3x + 1 + 5 . . . . eliminate parentheses, add 5

y = 1/3x +6 . . . . slope-intercept equation of the line

6 0

3 years ago

The perimeter of triangle B is 6 times greater than the perimeter of

neonofarm [45]

3 times greater than A

5 0

3 years ago