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egoroff_w [7]
3 years ago
5

Which of the following are solutions to the equation below?

Mathematics
1 answer:
insens350 [35]3 years ago
6 0

Answer:

- 5 -2 \sqrt{2}

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DAILY PRACTIC
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Answer:

yo what?

Step-by-step explanation:

the health is this you awnser le ? I uh what?

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3 years ago
How do you solve<br> 6x-2y=-4<br> y=3x+2
liq [111]
6x - 2y = - 4; y = 3x + 2

Now let's solve y = 3x + 2 for y
Substitute (3x + 2) for y in ↓↓↓
 6x - 2y = -4: \\ 6x - 2y = -4 \\ 6x - 2(3x +2) = -4 \\ -4 =-4 \\ -4+4=-4+4 \\ =0
8 0
3 years ago
What is the answer for this question?
Anit [1.1K]

Answer:

f

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The head librarian at the Library of Congress has asked her assistant for an interval estimate of the mean number of books check
Verdich [7]

Answer:

n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11

So the answer for this case would be n=11 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma =150 represent the population standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The confidence interval for this case is given by: (740, 920)

We can find the estimate for the mean and we got:

\bar X = \frac{740+920}{2} = 830

and the margin of error is given by :

ME = \frac{920-740}{2}= 90

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =90 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11

So the answer for this case would be n=11 rounded up to the nearest integer

5 0
3 years ago
Need help thanks don’t understand
kykrilka [37]

Answer:

You need help with what-?

7 0
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