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fredd [130]
3 years ago
7

The sand pit for the long jump has a width of 2.7 meters and a length of 9.54 meters. Just in case it rains, the principal wants

to cover the sand pit with a piece of plastic the night before the event. How many square meters of plastic will the principal need to cover the sand pit?
Mathematics
1 answer:
sveta [45]3 years ago
8 0

Answer:

A = 25.758 m²

Step-by-step explanation:

Width of the sand pit, b = 2.7 m

Length of the sand pit, l = 9.54 m

We want to cover the sand pit with a piece of plastic. We need to find how many square meters of plastic will be needed to cover the sand pit. It is equal to the area of sand pit. It is in the shape of rectangle. Its area is given by :

A = l × b

A = 2.7 × 9.54

A = 25.758 m²

So, 25.758 m² of plastic will be needed to cover the sand pit.

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Dafna1 [17]

Answer:

7.14

Step-by-step explanation:

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Mr. Fuller wants to put fencing around his rectangular-shaped yard. the width of the yard is 55 feet and the length is 75 feet.
AlekseyPX
260 feet. 55+55=110, 75+75=150, 150+110=260
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Please no "files": Simplify. Express your answer as the given base raised to a single exponent.
Kipish [7]

Answer:

9^48

Step-by-step explanation:

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5 0
2 years ago
Suppose the waiting times in an emergency room are normally distributed with a mean (mean) of 40 and a standard deviation (sigma
kipiarov [429]

Answer:

0.68269

Step-by-step explanation:

When we are to find the z score for population where a random sample is picked, the z.score formula we use is

z = (x-μ)/Standard error, where

x is the raw score,

μ is the population mean

Standard error = σ/√n

σ is the population standard deviation

n = random number of samples

For : x = 38 minutes, μ = 40, σ = 10, n = 5

z = 38 - 40/10 /√25

= -2/10/5

= -2/2

= -1

Determining the probability value using z table

P(x = 38) = P(z = -1)

= 0.15866

For : x = 42 minutes, μ = 40, σ = 10, n = 25

z = 42 - 40/10 /√25

= 2/10/5

= 2/2

= 1

Determining the probability value using z table

P(x = 42) = P(z = 1)

= 0.84134

The probability that their average waiting time will be between 38 and 42 minutes is calculated as

P(-Z<x<Z)

= P(-1 < x < 1)

= P(z = 1) - P(z = -1)

= 0.84134 - 0.15866

= 0.68269

Therefore, the probability that their average waiting time will be between 38 and 42 minutes is 0.68269

3 0
3 years ago
Evaluate x3 − 2y2 − 3x3 + z4 if x = 3, y = 5, and z = −3.
White raven [17]

Answer:

Step-by-step explanation:

x^3-2y^2-3x^3+z^4

(3)^3-2(5)^3+(-3)^4

-142

8 0
3 years ago
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