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fredd [130]
3 years ago
7

The sand pit for the long jump has a width of 2.7 meters and a length of 9.54 meters. Just in case it rains, the principal wants

to cover the sand pit with a piece of plastic the night before the event. How many square meters of plastic will the principal need to cover the sand pit?
Mathematics
1 answer:
sveta [45]3 years ago
8 0

Answer:

A = 25.758 m²

Step-by-step explanation:

Width of the sand pit, b = 2.7 m

Length of the sand pit, l = 9.54 m

We want to cover the sand pit with a piece of plastic. We need to find how many square meters of plastic will be needed to cover the sand pit. It is equal to the area of sand pit. It is in the shape of rectangle. Its area is given by :

A = l × b

A = 2.7 × 9.54

A = 25.758 m²

So, 25.758 m² of plastic will be needed to cover the sand pit.

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Can you guys help please im so confused
marissa [1.9K]

Answer:

a) see below

b) 40x20 meters

Step-by-step explanation:

Write down what you know:

- The area of the enclosure is length*width, so

A = x \cdot y

- The length of the fencing is 80 meters, so

2y + x = 80

Now we have to combine these two equations above, and get rid of y in the process.

First rewrite the second as:

y = 40 - \frac12 x

Then substitute for y in the first:

A = x (40 - \frac12 x) = 40x - \frac12x^2

b) To maximize A, find the zero of the first derivative:

A'(x) = 40 - x = 0 \implies x=40

So y = (80-40)/2 = 20 meters.

8 0
2 years ago
1. Each side of a square barn is 9 meters long.
oksian1 [2.3K]

Answer:

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Step-by-step explanation:

7 0
2 years ago
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artcher [175]

We have to translate the coordinates using the given rule.

The given rule is (x-4,y+3)

Now we have to translate the point A(4,6) using the given rule.

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