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fredd [130]
3 years ago
7

The sand pit for the long jump has a width of 2.7 meters and a length of 9.54 meters. Just in case it rains, the principal wants

to cover the sand pit with a piece of plastic the night before the event. How many square meters of plastic will the principal need to cover the sand pit?
Mathematics
1 answer:
sveta [45]3 years ago
8 0

Answer:

A = 25.758 m²

Step-by-step explanation:

Width of the sand pit, b = 2.7 m

Length of the sand pit, l = 9.54 m

We want to cover the sand pit with a piece of plastic. We need to find how many square meters of plastic will be needed to cover the sand pit. It is equal to the area of sand pit. It is in the shape of rectangle. Its area is given by :

A = l × b

A = 2.7 × 9.54

A = 25.758 m²

So, 25.758 m² of plastic will be needed to cover the sand pit.

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