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Blababa [14]
3 years ago
8

Will give brainliest... Please I need this answer so badly

Mathematics
1 answer:
m_a_m_a [10]3 years ago
8 0
(6 - x) * (6 + x) - ( (2 - x) * (2 + x) ) =

6^2 - x^2 - ( 2^2 - x^2 ) =

36 - x^2 - ( 4 - x^2 ) =

36 - x^2 - 4 + x^2 =

36 - 4 =

32 square feet
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Can someone please answer this please!
DaniilM [7]

Answer:

T = ±22

Step-by-step explanation:

Let's solve your equation step-by-step.

0=−16t2+7744

Step 1: Add 16t^2 to both sides.

0+16t2=−16t2+7744+16t2

16t2=7744

Step 2: Divide both sides by 16.

16t2

16

=

7744

16

t2=484

Step 3: Take square root.

t=±√484

t=22 or t=−22

6 0
3 years ago
Need help its hard sadly
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4 years ago
Hello can anyone help me please
Naya [18.7K]

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5.3 to the 4th power :)

Step-by-step explanation:

7 0
3 years ago
Integrate ​G(x,y,z)equalsz over the parabolic cylinder yequalszsquared​, 0less than or equalsxless than or equals2​, 0less than
yKpoI14uk [10]

I gather you're supposed to compute the integral of G(x,y,z)=z over a surface S that is the part of the parabolic cylinder y=z^2 with 0\le x\le2 and 0\le z\le\frac{\sqrt{15}}2.

We can parameterize S by

\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k

with the given constraints on x and z. Take the normal vector to S to be

\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k

so that the surface element is

\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz

Then in the integral, we have

\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}

5 0
3 years ago
the two cycles have center G where radius GI= 4ft, radius MG =6.5ft and MGC=72. Determine the total cost be to paint area MCAI i
Solnce55 [7]
I have no clue what the answer would be, I’ve worked on it for 25 minutes, I will get back to you if I figure it out :,)
4 0
3 years ago
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