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3 years ago

HELP ME RN PLEASEEEE [WILL GIVE BRAINLY TO CORRECT AND BEST EXPLAINED ANSWER]

Mathematics

2 answers:

tatuchka [14]3 years ago

8 0

D = 34 your welcome mark me please choice threee will be correct

VMariaS [17]3 years ago

6 0

Answer:

$\boxed {\boxed {\sf d= \sqrt{34}}}$

Step-by-step explanation:

We want to find the distance between two points, so the following formula is used.

$d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Where (x₁, y₁) and (x₂, y₂) are the points we are finding the distance between.

We are given the points (-2, -1) and (3,2). If we match the corresponding value and variable we see that:

x₁= -2
y₁= -1
x₂= 3
y₂= 2

Substitute the values into the formula.

$d= \sqrt {(-2-3)^2+(2--1)^2$

Solve the parentheses.

-2 -3 = -5
2--1 = 2+ 1 = 3

$d= \sqrt{(-5)^2+(3)^2$

Solve the exponents.

(-5)²= -5*-5= 25
(3)²= 3*3=9

$d= \sqrt{25+9}$

Add.

$d= \sqrt{34}$

This radical cannot be simplified, so the distance between the two points is √34 and choice 3 is correct.

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Answer:

1 no

2 I don't know

3 no

4 yes

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6 -0.5

7 no slope

Step-by-step explanation:

1 no because the y overlaps

2 not sure

3 it over laps

4 it never overlaps

5 y=2.5x-3

6 y=-0.5x+1

7 no slope it's just x=-2

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y=mx+b

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3 0

3 years ago

What do you say when you see an empty parrot cage?

irina1246 [14]

Oh no my parrot is missing

5 0

3 years ago

Calculate pt3 such that a line from pt1 to pt3 is perpendicular to the line from pt1 to pt2, and the distance between pt1 and pt

Leni [432]

Let the point_1 = p₁ = (1,4)
and      point_2 = p₂ = (-2,1)
and      Point_3 = p₃ = (x,y)

The line from point_1 to point_2 is L₁ and has slope = m₁
The line from point_1 to point_3 is L₂ and has slope = m₂
m₁ = Δy/Δx = (1-4)/(-2-1) = 1
m₂ = Δy/Δx = (y-4)/(x-1)
L₁⊥L₂ ⇒⇒⇒⇒ m₁ * m₂ = -1
∴ (y-4)/(x-1) = -1 ⇒⇒⇒ (y-4)= -(x-1)
(y-4) = (1-x) ⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒ equation (1)

The distance from point_1 to point_2 is d₁
The distance from point_1 to point_3 is d₂
d = $\sqrt{Δx^2+Δy^2}$
d₁ = $\sqrt{(-2-1)^2+(1-4)^2}$
d₂ = $\sqrt{(x-1)^2+(y-4)^2}$
d₁ = d₂
∴ $\sqrt{(-2-1)^2+(1-4)^2} = \sqrt{(x-1)^2+(y-4)^2}$ ⇒⇒ eliminating the root
∴(-2-1)²+(1-4)² = (x-1)²+(y-4)²
(x-1)²+(y-4)² = 18
from equatoin (1) y-4 = 1-x
∴(x-1)²+(1-x)² = 18            ⇒⇒⇒⇒⇒ note: (1-x)² = (x-1)²
2 (x-1)² = 18
(x-1)² = 9
x-1 = $\pm \sqrt{9} = \pm 3$
∴ x = 4 or x = -2
∴ y = 1 or y = 7

Point_3 = (4,1) or (-2,7)

8 0

4 years ago

Answer this question show you’re work

Svetlanka [38]

Answer:

Step-by-step explanation:

The answer is x=-4 the work is shown on the pic