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amm1812
3 years ago
14

8 divided by 832 (long division)

Mathematics
1 answer:
Artyom0805 [142]3 years ago
8 0

Answer:

Step-by-step explanation:

832/8 math problems division = 104. Therefore 104 to 2 decimal places= 104

832/8 divided by 2 » (832/8) ÷ 2 » 104 ÷ 2 = 52

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How do you simplify <img src="https://tex.z-dn.net/?f=7%5Csqrt%5B4%5D%7B80pq%5E%7B2%7Dr%5E%7B8%7D%20%20%7D" id="TexFormula1" tit
kondor19780726 [428]

Answer:

14 ( 5)^{\frac{1}{4}} p^{\frac{1}{4}} q^{\frac{1}{2}} r^{2}

Step-by-step explanation:

The expression to simplify in this problem is

7\sqrt[4]{80pq^2r^8}

Which can be rewritten as

7(80pq^2r^8)^{\frac{1}{4}}

Or also as

7\cdot 80^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot (q^2)^{\frac{1}{4}} \cdot (r^8)^{\frac{1}{4}}

Now we can apply the following rule for the calculation of the power of a power:

(a^m)^n = a^{m\cdot n}

So we get:

7\cdot 80^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}

Which can therefore be rewritten as

7\cdot (2^4\cdot 5)^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}

And so, we get

7\cdot 2 \cdot ( 5)^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}

which can be finally rewritten as

14 ( 5)^{\frac{1}{4}} p^{\frac{1}{4}} q^{\frac{1}{2}} r^{2}

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