The scale factor of the scale drawing of a mirror to the actual mirror is

Emegergency asap or my mom will kill me. first off it can be. Consider the triple 6, 8, and 10.

Anastaziya [24]

Answer:

Yes: (3,4,5)

Step-by-step explanation:

10² = 6² + 8²

(10/2)² = (6/2)² + (8/2)²

5² = 3² + 4²

25 = 9 + 16

25 = 25

The sides satisfy the pythagoras theorem

10 is the hypotenuse, 6 & 8 are the legs

5 is the hypotenuse, 3 & 4 are the legs

5 0

3 years ago

Find the mean, range, and interquartile range of the heights of plants given

Artist 52 [7]

Answer:

Mean = 30.9

Range = 80

Interquartile Range = 36

Step-by-step explanation:

The mean of a set of numbers is the sum divided by the number of terms. In other words that means 2, 22, 4, 36, 82, 44, 65, 30, 8, 16 go over a fraction like this. There are 10 numbers here so this is our denominator.

$\frac{2+ 22 + 4 + 36 + 82 + 44 + 65 + 30 + 8 + 16}{10}$

$\frac{309}{10} > 30.9$

For the range, all we do is subtract the minimum value from the maximum which is 82 - 2. That gives us 80.

For the IQ Range....

Arrange the terms in ascending order.

2, 4, 8, 16, 22, 30, 36, 44, 65, 82

Then we need to find the median which is the average of the two middle terms.

$\frac{22+30}{2} > \frac{2*11 + 30}{2} >\frac{2*11+2*15}{2} > \frac{2 * (11 + 15)}{2} > 11 + 15 > 26$

So for the lower half of data 2, 4, 8, 16, 22 we have the median of 8

And for the upper half 30, 36, 44, 65, 82 we have the median of 44.

To find the IQ Range it is the difference between the first quartile (8) and the third (44)

So 44 - 8 = 36

7 0

2 years ago

Read 2 more answers

Help plz :) Solve for A A.45 B.25 C.115 D.10

Tatiana [17]

Its a right angle so 65 take away from 90 is 25

6 0

4 years ago

The average fun size Snickers bar has the mass of 20.1 grams with a standard deviation of 0.7 grams What percent of Snickers bar

Alex Ar [27]

Step-by-step explanation:

The “fun size” of a Snickers bar is supposed to weigh 20 grams. Because the penalty for selling Snickers candy bars that weigh less than 20 grams is so severe, the manufacturer calibrates the machine so that the mean weight is 20.2 grams. The quality control manager at the candy company is concerned that the candy produced does not weigh 20.2 grams. She obtains a random sample of 64 candy bars and weighs them. She finds that the mean weight of this sample is 20.05 grams with standard deviation 0.72. By answering the following questions, test the claim that the Snickers bars have a mean weight less than 20.2 grams at the level of α = 0.01.

1. Select from the following list all the requirements that are met in this problem scenario for this test: (circle your choice(s))

a. The population is approximately normal.

b. The population standard deviation is known.

c. The sample taken is a random sample.

d. The population standard deviation is unknown. e

. The degrees of freedom is 0.01.

f. The sample size is greater than 30.

2. Which of the following statements is correct?

a) Parameters describe sample characteristics.

b) Statistics describe population characteristics.

c) We use statistics to estimate the value of parameters.

d) We use parameters to estimate the value of statistics

Expert Answer

3 0

3 years ago

Why is 4b-7-3b+9 equal to b+2

rodikova [14]

The first expression can be simplified by combining like terms.

First, the terms "4b" and "-3b" can be combined to form "b"
Then, the terms "-7" and "9" can be combined to form "2"

Finally, we simply put these two final terms together, to form "b+2"

Hence, 4b-7-3b+9 is equal to be + 2.

Hope this helps!

8 0

3 years ago