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The energy in the capacitor at the instant after the switch is closed, based on the potential across the capacitor is 31 mJ
<h3>What is the energy amount in the capacitor?</h3>
Because total energy is constant, this can be found by the formula:
= Initial energy in capacitor - Energy in inductor
The initial energy in the capacitor is:
= 0.5 x 4 x 10⁻⁶ x 200²
= 0.08J
The energy in the inductor is:
= 0.5 x 0.2 x 0.7²
= 0.049
The energy in the capacitor at that instant is:
= 0.08 - 0.049
=0.031 j
= 31 J
Find out more on the energy in the capacitor at brainly.com/question/27960614
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Answer: {y∈R: y≤6} or [6,∞)
Explanation:
This problem doesn't require too much math. If you look at the equation given, you can see that it is a quadratic equation in the form of
. Since this is a quadratic equation, we have an idea of that the graph would look like. It either curves up or down. Since this is a positive equation, 
, we know that this is going to curve up. In order to find the minimum of the curve, you would use 
.
This means the x value of the parabola is -2. To find the y, you plug -2 into the original equation.
Now that we know the y value of the minimum/vertex is 6, and it is determined that the parabola curves up, the range is y≤6 because the range starts at 6 and goes off toward infinity.
