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gulaghasi [49]
3 years ago
5

HELP PLEASE QUICKLY!!!!!!!!! NO LINKS

Mathematics
1 answer:
3241004551 [841]3 years ago
7 0

Answer:

80mi

Step-by-step explanation:

65+0.70m <121

0.70m< 56

m<80

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Sophie [7]

Answer:

B.

Step-by-step explanation:

I graphed it but you could also use the y intercept to determine which function matches the graph

log(x+1)<u>+3</u>

the +3 at the end of the function makes the y-intercept positive 3

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3 years ago
Which operation would you do first?
shepuryov [24]

Answer:

addition +

Step-by-step explanation:

You always do what's in parenthesis first.

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Answer:

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8 0
3 years ago
(20pts) Prove that the product of any two odd numbers is always odd. Make sure to explain your proof​
kozerog [31]

Answer:

See below (I hope this helps!)

Step-by-step explanation:

Because odd numbers are always 1 greater than even numbers, we can call the two odd numbers x + 1 and y + 1 where x and y are even integers. Multiplying the two gives us:

(x + 1) * (y + 1)

= x * y + x * 1 + 1 * y + 1 * 1

= xy + x + y + 1

We know that x * y will be even because x and y are also even and the sum of two even numbers will be even, and we also know that x and y are even and that 1 is odd. Since the sum of even and odd numbers is always odd, the product of any two numbers is always odd.

*NOTE: I put a limitation on x and y in my proof (the limitation was that x and y must be EVEN integers) but you don't have to do that, you could make the odd integers 2x + 1 and 2y + 1 where x and y could be any integer from the set Z like mirai123 did. I simply gave this proof because it was the first thing that came to mind. While mirai123's proof and mine are different, they are still both correct.

5 0
2 years ago
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