Answer:
Summary:
We conclude that:
Table B and Graph A represents the equation.
Hence, option D represents the equation.
Step-by-step explanation:
Given the equation
y = 5x
<u>CHECKING TABLE A</u>
x y
5 1
10 2
15 3
substituting x = 5 in the equation
y = 5x
y = 5(5)
y = 25
Thus,
at x = 5, y = 25
Hence,
(5, 25) does not satisfy the table A.
substituting x = 10 in the equation
y = 5x
y = 5(10)
y = 50
Thus,
at x = 10, y = 50
Hence,
(10, 50) does not satisfy the table A.
substituting x = 15 in the equation
y = 5x
y = 5(15)
y = 75
Thus,
at x = 15, y = 75
Hence,
(15, 75) does not satisfy the table A.
Conclusion:
Table A does not represent the equation y = 5x
CHECKING TABLE B
x y
1 5
2 10
3 15
substituting x = 1 in the equation
y = 5x
y = 5(1)
y = 5
Thus,
at x = 1, y = 5
Hence,
(1, 5) satisfies the table B.
substituting x = 2 in the equation
y = 5x
y = 5(2)
y = 10
Thus,
at x = 2, y = 10
Hence,
(2, 10) satisfies the table B.
substituting x = 3 in the equation
y = 5x
y = 5(3)
y = 15
Thus,
at x = 3, y = 15
Hence,
(3, 15) satisfies the table B.
Conclusion:
Table A represents the equation y = 5x
<u>CHECKING GRAPH A</u>
Given the equation
y = 5x
It is clear from graph A that
at x = 1, y = 5
at x = 2, y = 10
at x = 3, y = 15
Also
Putting x = 0,
y = 5(0) = 0
Thus, at x = 0, y = 0
Aso the table indicates that at x = 0, y = 0
Thus, the graph represents the equation y = 5x.
<u>CHECKING GRAPH B</u>
y = 5x
Putting x = 0,
y = 5(0) = 0
Thus, at x = 0, y = 0
But, the table B indicates that at x = 0, y = 5.
Thus, graph B does not represent the equation
Summary:
We conclude that:
Table B and Graph A represents the equation.
Hence, option D represents the equation.
