All categories

3 years ago

4.

Mathematics

2 answers:

Tom [10]3 years ago

4 0

Answer:

A. $2.20; $2.54

Step-by-step explanation:

Contact [7]3 years ago

3 0

Answer:

A. $2.20; $2.54

Step-by-step explanation:

It should give you 2.54.

First, you have to multiply 2.7 miles times .20 miles. It gives you .54, which you are supposed to add 2.00 to it for every ride.

c =0.20m + 2.00

Where c is the cost and m = number of miles,

For a 2.7 mile ride, m = 2.7

c = 0.20m + 2.00, m = 2.7

c = 0.20*2.7 + 2

c = 0.54 + 2

c = 2.54

Charge for the ride = $2.54

I hope this helps.

You might be interested in

Lines b and a are intersected by line f. At the intersection of lines f and b, the bottom left angle is angle 4 and the bottom r

Minchanka [31]

Answer:

m∠1 = 110° and m∠3 = 70°

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

Suppose that P[infinity] n=0 cnx n converges when x = −5 and diverges when x = 7. What can be said about the convergence or dive

bezimeni [28]

What can be said about the convergence or divergence of the following series? summation n=0 to infinite (-1)^n Cn9^n

Answer:

The series diverges

Step-by-step explanation:

Given.

The center of convergence of the series, ΣCnx^n = 0 (for n = 0 to ∞)

The interval of the convergence is of the form (-k,k)

One or both the end points may be included in the intervals of convergence.

Also, given that the series diverges when x = 7; this implies that the interval of convergence is smaller than {-7,7}

The series

Σ(-1)^n Cn9^n (for n = 0 to ∞)

= Σ Cn(-9)^n (for n = 0 to ∞)

This is obtained after substituting -9 for x in ΣCnx^n = 0

So, x = -9

This is outside the boundary {-7,7}.

Hence, the given series diverges

7 0

4 years ago

The circumference of Z is 84 cm. What is the length of xy (the minor arc)?

Orlov [11]

Answer:21 cm

Step-by-step explanation: The circle's circumference is 84 cm. 84 / 4 = 21. Therefore the length of the arc XY is 21 cm.

6 0

3 years ago

Solve the given inequality :

tigry1 [53]

Answer:

x < -5 or x = 1 or 2 < x < 3 or x > 3

Step-by-step explanation:

Given rational inequality:

$\dfrac{(x-1)^2(x-2)^3}{(x^2-5x+6)^2(x+5)}\geq 0$

$\textsf{Factor }(x^2-5x+6):$

$\implies x^2-2x-3x+6$

$\implies x(x-2)-3(x-2)$

$\implies (x-3)(x-2)$

Therefore:

$\dfrac{(x-1)^2(x-2)^3}{(x-3)^2(x-2)^2(x+5)}\geq 0$

Find the roots by solving f(x) = 0 (set the numerator to zero):

$\implies (x-1)^2(x-2)^3=0$

$\implies (x-1)^2=0\implies x=1$

$\implies (x-2)^3=0 \implies x=2$

Find the restrictions by solving f(x) = undefined (set the denominator to zero):

$\implies (x-3)^2(x-2)^2(x+5)=0$

$\implies (x-3)^2=0 \implies x=3$

$\implies (x-2)^2=0 \implies x=2$

$\implies (x+5)=0 \implies x=-5$

Create a sign chart, using closed dots for the roots and open dots for the restrictions (see attached).

Choose a test value for each region, including one to the left of all the critical values and one to the right of all the critical values.

Test values: -6, 0, 1.5, 2.5, 4

For each test value, determine if the function is positive or negative:

$f(-6)=\dfrac{(-6-1)^2(-6-2)^3}{(-6-3)^2(-6-2)^2(-6+5)}=\dfrac{(+)(-)}{(+)(+)(-)}=+$

$f(0)=\dfrac{(0-1)^2(0-2)^3}{(0-3)^2(0-2)^2(0+5)}=\dfrac{(+)(-)}{(+)(+)(+)}=-$

$f(1.5)=\dfrac{(1.5-1)^2(1.5-2)^3}{(1.5-3)^2(1.5-2)^2(1.5+5)}=\dfrac{(+)(-)}{(+)(+)(+)}=-$

$f(2.5)=\dfrac{(2.5-1)^2(2.5-2)^3}{(2.5-3)^2(2.5-2)^2(2.5+5)}=\dfrac{(+)(+)}{(+)(+)(+)}=+$

$f(4)=\dfrac{(4-1)^2(4-2)^3}{(4-3)^2(4-2)^2(4+5)}=\dfrac{(+)(+)}{(+)(+)(+)}=+$

Record the results on the sign chart for each region (see attached).

As we need to find the values for which f(x) ≥ 0, shade the appropriate regions (zero or positive) on the sign chart (see attached).

Therefore, the solution set is:

x < -5 or x = 1 or 2 < x < 3 or x > 3

As interval notation:

$(- \infty,-5) \cup x=1 \cup (2,3) \cup(3,\infty)$

4 0

2 years ago

Find the value of something 11/12=something/48

Thepotemich [5.8K]

12x4=48
11x4=44
44/48

6 0

3 years ago

Read 2 more answers