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MrRissso [65]
3 years ago
6

A triangle has three angles of 36°, 34°, and 110°. A. equilateral B. obtuse C. acute D. right

Mathematics
2 answers:
dem82 [27]3 years ago
5 0
Obtuse because of the 110° angle
Anika [276]3 years ago
5 0

Answer:

Obtuse Triangle.

Step-by-step explanation:

An obtuse-angled triangle is a triangle in which one of the interior angles measures more than 90° degrees. In this case, 110° is more than 90°. So, its an obtuse angle. If one angle of the triangle is obtuse, then the other two angles with always be acute.

Hence, this is an obtuse triangle

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SIMPLE MATH PROBLEM PLZ ANSWER<br><br> u can pick more than one..
7nadin3 [17]

its the first one 6k - 5

if u were to distribute u need to remember that 6 is negative so it changes -k to a positive 6k and then you would time 4 by -6 which would be -24 but u would just write it like 19 + 6k - 24. then u would add 19 to both sides by 19 which would be like adding 19 to -24 which would equal to -5 so it would equal to 6k - 5.

hope I explained the steps well enough for you.

5 0
4 years ago
What’s the value of x in each triangle?
vazorg [7]

Answer:

<u> </u><u>The</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>is</u><u> </u><u>7</u><u>0</u><u>°</u><u>.</u>

Step-by-step explanation:

Let's name the angle to the right of 125° as 'y'.

y = 180 - 125 (linear pair)

<u>y = 55</u>°

Now, we know that all the angles in a triangle sum up to 180°. (Angle Sum Property)

x = 180 - (55+55)

x = 180 - 110

<u>x</u><u> </u><u>=</u><u> </u><u>7</u><u>0</u><u>°</u>

8 0
3 years ago
(3 points) Determine whether each of these functions f : {a, b, c, d} → {a, b, c, d} is one-to-one and whether each of these fun
finlep [7]

Answer:

Step-by-step explanation:

Recall the following. Given a function f we say that  

f is one to one if for x,y in the domain of f and f(x)=f(y) then x=y.

This means that there are no different elements in the domain of the function  that are linked to the same value.

f is onto if for every y in the codomain of f, then there is an element x in the domain of f such that f(x) = y. That is, given an element y in the codomain of f, there exists and element in the domain that is linked to y.

a)  

f(a) =b, f(b)=a, f(c) = c, f(d) = d. Note that this function links each element in {a,b,c,d} to different elements in {a,b,c,d}, so it is a one to one function. Since for every element x in {a,b,c,d} there is an element y in {a,b,c,d} such that f(y) = x, then this function is also onto.  

b)  

f(a)=b, f(b) = b, f(c) = d, f(d) = c. Note that the elements a,b are linked both to b, so this function fails to be one-to-one. Also, note that the element a has no element x in {a,b,c,d} such that f(x) = a, so this function fails to be onto.  

c)  

f(a) = d, f(b) = b, f(c) = c, f(d) = d.  

As in b), since a and d are linked to d, then this function is not one to one. Also, since the element a has no element x in {a,b,c,d} such that f(x) = a, then it also fails to be onto.  

8 0
3 years ago
Which equation is true?<br><br> 1. 5+0=0<br> 2. 15x0=0<br> 3. 1.4+2.7=4.1<br> 4. 2/3 x 5/9 = 7/12
katrin2010 [14]
1.4+2.7=4.1 is true the others are false
8 0
3 years ago
Read 2 more answers
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maksim [4K]

16

find the absolute values ie. 9 and 2

multiply 9 by 2 and subtract 2 by 18

3 0
3 years ago
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