I=k/d^2
4=k/d^2 and 1=k/64 so if we divide the first by the second we get:
4/1=(k/d^2)/(k/64)
4=(k/d^2)*(64/k)
4=64/d^2
d^2=64/4
d^2=16
d=4 meters
(2, 0) (2, 7) assuming that Y can equal anything.
<span>V = 1/3(3.14)r^2h
=1.046r^2h
Solving for V </span>
Answer:
5,7
Step-by-step explanation:
Answer:
option (b) 0.0228
Step-by-step explanation:
Data provided in the question:
Sample size, n = 100
Sample mean, μ = $20
Standard deviation, s = $5
Confidence interval = between $19 and $21
Now,
Confidence interval = μ ± 
thus,
Upper limit of the Confidence interval = μ + 
or
$21 = $20 + 
or
z = 2
Now,
P(z = 2) = 0.02275 [From standard z vs p value table]
or
P(z = 2) ≈ 0.0228
Hence,
the correct answer is option (b) 0.0228