Janine rented an aprtment for 900 a month after a 1year she bought a house
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Ok so there are no real solutions for xy=15000 and x+y=5
there are immaginary solutions though so
xy=15000
x+y=5
x+y=5
y=5-x
x(5-x)=15000
-x^2+5x=15000
0=x^2-5x+15000
quadriacic formula
if ax^2+bx+c=0, then
x=
x^2-5x+15000
a=1
b=-5
c=15000
x=
x=
x=
x=
so the numbers are
and 
there are immaginary solutions though so
xy=15000
x+y=5
x+y=5
y=5-x
x(5-x)=15000
-x^2+5x=15000
0=x^2-5x+15000
quadriacic formula
if ax^2+bx+c=0, then
x=
x^2-5x+15000
a=1
b=-5
c=15000
x=
x=
x=
x=
so the numbers are