Answer:
Final answer is ![x-6y=23](https://tex.z-dn.net/?f=x-6y%3D23)
Step-by-step explanation:
We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).
So first we need to find the slope of given line.
rewirite x=6y-5 in y=mx+b form
x+5=6y
![\frac{1}{6}x+\frac{5}{6}=y](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7Dx%2B%5Cfrac%7B5%7D%7B6%7D%3Dy)
Compare given equation with y=mx+b
we get: m=1/6
We know that parallel equations has equal slope.
Then slope of required line m=1/6
Now plug the given point (5,-3) and slope m=1/6 into point slope formula:
![y-y_1=m\left(x-x_1\right)](https://tex.z-dn.net/?f=y-y_1%3Dm%5Cleft%28x-x_1%5Cright%29)
![y-(-3)=\frac{1}{6}\left(x-5\right)](https://tex.z-dn.net/?f=y-%28-3%29%3D%5Cfrac%7B1%7D%7B6%7D%5Cleft%28x-5%5Cright%29)
![y+3=\frac{1}{6}x-\frac{5}{6}](https://tex.z-dn.net/?f=y%2B3%3D%5Cfrac%7B1%7D%7B6%7Dx-%5Cfrac%7B5%7D%7B6%7D)
![y=\frac{1}{6}x-\frac{5}{6}-3](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B6%7Dx-%5Cfrac%7B5%7D%7B6%7D-3)
![y=\frac{1}{6}x-\frac{23}{6}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B6%7Dx-%5Cfrac%7B23%7D%7B6%7D)
Now we need to rewrite that equation in standard form. Ax+By=C.
6y=x-23
x-23=6y
x-6y=23
Hence final answer is ![x-6y=23](https://tex.z-dn.net/?f=x-6y%3D23)
Answer:
G) y=3x+1
Step-by-step explanation:
1 would equal b = y-intercept
-3 is the slope = m
y-intercept form is y=mx+b
plug it in
y=-3x+1
Answer:
2/5
Step-by-step explanation:
Answer:
angle Lmp=77degrees and angle nmp = 103degrees