Answer:
1. 0.0417
2. 0.1375
3. no
Step-by-step explanation:
lets define:
A as the probability that a car needs a warranty repair.
B as probability taht the car is manufactured by a company that is based in country X
we have the
prob(A) = 0.08
prob(B) = 0.60
prob(A∩B) = 0.025
a. we are to calculate the probability taht a car manufactured in country X needs a warranty repair.
= p(AIB) =
= 0.025/0.60
= 0.0417
2. Probability that car needs warranty repair given it was not manufactured in country X.
P(AIB')
= p(A∩B')/P(B')
= 0.08-0.025/1-0.60
= 0.055/0.40
= 0.1375
3. no, Need for warranty repair and location are not independent
Answer:
(r+s) (x) = 4x+3
(r*s) (x) = 3x^2 +x-4
(r-s) (-1) = -3
Step-by-step explanation:
r(x) = x-1
s(x) = 3x+4
(r+s) (x) = x-1 + 3x+4
Combine like terms
= 4x+3
(r*s) (x) = ( x-1) ( 3x+4)
FOIL
= 3x^2 +4x-3x-4
= 3x^2 +x-4
(r-s) (x) = x-1 - (3x+4)
Distribute the minus sign
=x-1-3x-4
=-2x-5
Let x = -1
(r-s) (-1) = -2(-1) -5
2-5
-3
Answer:
b is answers for the question and
Step-by-step explanation:
please give me brainlest
One $5 and 9 $2 because 2x9 is 18 and 18+5 is 23