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Anettt [7]
3 years ago
15

Answer and please show the work !

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
8 0

Answer:

Option A for part A and $79 for part B

Step-by-step explanation:

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The number p and 2/3 are additive inverses.
vlada-n [284]

By knowing that p and 2/3 are additive inverses, we will see that p = -2/3

So two numbers A and B are additive inverses if:

A + B = 0

Here the two numbers are p and 2/3, so we have:

2/3 + p = 0

Solving this for p gives:

p = -2/3

Then the value of p is just -2/3.

Now, I can't "drag and drop" the labels in the given image, so I will post a little graph of where each point should be:

If you want to learn more about additive inverses, you can read:

brainly.com/question/16681279

6 0
3 years ago
What is the fifth term in the geometric sequence?<br> 1, 2, 4, 8,
olga55 [171]

Answer:

16

Step-by-step explanation:

8 0
3 years ago
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What is the volume of the cone below?
bagirrra123 [75]

Answer:

B. 3408pi

Step-by-step explanation:

formula volume of cone = 1/3 x pi x r x r x h

volume = 1/3 x pi x 12 x 12 x 71

= 3408pi

3 0
3 years ago
How many yards are in 150 feet?
aliya0001 [1]
Each yard is 3 feet, so 150 / 3(a yard) = 50 (yards)
4 0
3 years ago
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Please can I have an explanation also, I am terrible at these kinds of questions!
wlad13 [49]

Answer:

<em>The fraction of the beads that are red is</em>

Step-by-step explanation:

<u>Algebraic Expressions</u>

A bag contains red (r), yellow (y), and blue (b) beads. We are given the following ratios:

r:y = 2:3

y:b = 5:4

We are required to find r:s, where s is the total of beads in the bag, or

s = r + y + b

Thus, we need to calculate:

\displaystyle \frac{r}{r+y+b}       \qquad\qquad    [1]

Knowing that:

\displaystyle \frac{r}{y}=\frac{2}{3}      \qquad\qquad    [2]

\displaystyle \frac{y}{b}=\frac{5}{4}

Multiplying the equations above:

\displaystyle \frac{r}{y}\frac{y}{b}=\frac{2}{3}\frac{5}{4}

Simplifying:

\displaystyle \frac{r}{b}=\frac{5}{6}       \qquad\qquad    [3]

Dividing [1] by r:

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+y/r+b/r}

Substituting from [2] and [3]:

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+3/2+6/5}

Operating:

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{\frac{10+3*5+6*2}{10}}

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{10+15+12}

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{37}

The fraction of the beads that are red is \mathbf{\frac{10}{37}}

8 0
3 years ago
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