Answer:
Probability at least one car will get punctured: 0.39347
Step-by-step explanation:
B(10,000 , 0.00005)
P(X ≥ 1) = 1 - P(X = 0)
= 1 - (1 - 0.00005)^10,000
= 1 - (0.99995)^10,000
= 1 - 0.60652...
= 0.39347 (probability that at least one car will get punctured)
As you can tell P(X ≥ 1) as we have to solve for the probability that at least one car will get punctured. That is of course 1 - [ P(X = 0) ].
So,
There are 7 cherry gumballs and 6 grape gumballs.
The total gumballs is 13.
Therefore, the ratio of grape gumballs to total gumballs is 6:13.
The answer is <span>A. .357 + .372 + .350 + .349 + x = 1.754; .326
</span>
x1 - average of <span>1999 Nomar Garciaparra Boston
</span>x2 - average of 2000 Nomar Garciaparra Boston
x3 - average of <span>2001 Ichiro Suzuki Seattle
</span>x4 - average of Manny Ramirez Boston
x - average of <span>2003 Bill Mueller Boston
</span><span>The sum of these five batting averages is 1.754:
x1 + x2 + x3 + x4 + x = 1.754
From the table:
x1 = 0.357
x2 = 0.372
x3 = 0.350
x4 = 0.349
x = ?
<u>0.357 + 0.372 + 0.350 + 0.349 + x = 1.754</u>
1.428 + x = 1.754
x = 1.754 - 1.428
<u>x = 0.326</u></span>
Answer:
c. 38
Step-by-step explanation:
D a kilogram is 100000 bigger
