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3 years ago

Solve the equation !!!!!!!

Mathematics

1 answer:

patriot [66]3 years ago

7 0

Answer:

x= 5pi/4, 7pi/4

Step-by-step explanation:

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Find the value of x. Write your answer in simplest form. WILL MAKE BRAINLIEST

lana [24]

2x^2=(3root2)^2
2x^2=9(2)
x^2=9
x= 3,-3

x=3 because your side length can’t be negative.

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3 years ago

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Which of the following is the solution to | X-13 |< 18 ?

Furkat [3]

Answer:

A. x<31 and x > -5

Step-by-step explanation:

| X-13 |< 18

Seperate into 2 equations, one positive and one negative, remembering to flip the inequality for the negative

x-13 < 18 and x -13 > -18

Add 13 to each side

x-13+13 < 18+13 and x-13+13> -18+13

x < 31 and x>-5

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3 years ago

Mr. Kugler gave the same geometry test to his 1st and 2nd period classes. The box and whisker plot summarizes the scores of each

Brums [2.3K]

D) The median of 2nd Period is greater than the median of 1st Period.

The one that's true

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2 years ago

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William carefully looked over a _____ before he signed it and moved into his new apartment. warranty lease credit report loan ap

Ber [7]

Answer:

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3 years ago

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Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0

3 years ago