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inysia [295]
3 years ago
5

HELP AM ABOUT TO GET AND F!!!

Mathematics
1 answer:
vlabodo [156]3 years ago
7 0
Slope would be D, -2/3
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Find all real solutions and show work: <br> 2x^3-3x^2+18x-27=0
Amiraneli [1.4K]

Given:

The given equation is

2x^3-3x^2+18x-27=0

To find:

All the real solutions.

Solution:

We have,

2x^3-3x^2+18x-27=0

It can be written as

x^2(2x-3)+9(2x-3)=0

(2x-3)(x^2+9)=0

Using zero product property, we get

(2x-3)=0 and (x^2+9)=0

2x=3 and x^2=-9

x=\dfrac{3}{2} and x=\pm\sqrt{-9}

We know that x=\pm\sqrt{-9} is an imaginary number because there is a negative sign under the square root.

Therefore, x=\dfrac{3}{2} is the only real solution of the given equation.

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