Answer:
x < -4.5
Step-by-step explanation:
<u>Step 1: Solve for x</u>
-10x / -10 > 45 / -10
When dividing or multiplying by a negative, the sign flips.
x < -4.5
Answer: x < -4.5
Answer:
x=2√5
Step-by-step explanation:
<u>1st method:</u>
sin(30)=opposite/hypotenuse=√5/x
sin(30)x=√5
x=√5/sin(30)
x=2√5
<u>2nd method:</u>
cos(60)=adjacent/hypotenuse=√5/x
cos(60)x=√5
x=√5/cos(60)
x=2√5
<u>3rd method:</u>
This is a 30-60-90 triangle, so we can multiply the short side, √5, by 2, to get x=2√5
Answer:
11 weeks
Step-by-step explanation:
First we need to check what variables we have.
Beginning Balance = $1000
Goal = $350
Withdrawal = $55 per week
Now let's declare a variable as the number of weeks.
Let x = number of weeks
1000 - 55x = 350
-55x = 350-1000
-55x = -650
Then we divide both sides by -55 to find the value of x.
x = 11.81 or 11 since we're looking for how many weeks in total
Now let's see if we still have 350 if we have a total of 11 as the value of x.
1000 - 55(11) = 350
1000 - 605 = 350
395 = 350
We can see that Kendall will have $395 compared to the $350 goal.
So Kendall can withdraw $55 a week for 11 weeks to still be within her goal of having $350 in her savings account.
Subtract 1111 from both sides
5{e}^{{4}^{x}}=22-115e4x=22−11
Simplify 22-1122−11 to 1111
5{e}^{{4}^{x}}=115e4x=11
Divide both sides by 55
{e}^{{4}^{x}}=\frac{11}{5}e4x=511
Use Definition of Natural Logarithm: {e}^{y}=xey=x if and only if \ln{x}=ylnx=y
{4}^{x}=\ln{\frac{11}{5}}4x=ln511
: {b}^{a}=xba=x if and only if log_b(x)=alogb(x)=a
x=\log_{4}{\ln{\frac{11}{5}}}x=log4ln511
Use Change of Base Rule: \log_{b}{x}=\frac{\log_{a}{x}}{\log_{a}{b}}logbx=logablogax
x=\frac{\log{\ln{\frac{11}{5}}}}{\log{4}}x=log4logln511
Use Power Rule: \log_{b}{{x}^{c}}=c\log_{b}{x}logbxc=clogbx
\log{4}log4 -> \log{{2}^{2}}log22 -> 2\log{2}2log2
x=\frac{\log{\ln{\frac{11}{5}}}}{2\log{2}}x=2log2
Answer= −0.171