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Amanda [17]
3 years ago
8

HELP I NEED HELP ASAP

Mathematics
1 answer:
poizon [28]3 years ago
6 0

Answer:

I will tell D or C but I'm not sure :-\

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Given: AY and BX bisect each other, PROVE: triangle ABJ and YJX are congruent...help me
Tamiku [17]
I would say acute If I am wrong sorry
3 0
4 years ago
Find the missing number. 4/5 = ?/45
Bogdan [553]
4/5 = ?/45

5 times 9 = 45.
What we do to the denominator must be done to the top, as well. 4 times 9 = 36.

So, the missing number is 36.
3 0
2 years ago
A medical researcher needs 37 people to test the effectiveness of an experimental drug. If 101 people have volunteered for the t
Rashid [163]

Answer:

The number of ways to select 37 people from 101 is, 5,397,234,129,638,871,133,346,507,775.

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!\cdot (n-k)!}

Compute the number of ways to select 37 people from 101 as follows:

{101\choose 37}=\frac{101!}{37!\cdot (101-37)!}

        =\frac{101!}{37!\times 64!}\\\\=\frac{101\times 100\times 99\times....64!}{37!\times 64!}\\\\=5397234129638871133346507775

Thus, the number of ways to select 37 people from 101 is, 5,397,234,129,638,871,133,346,507,775.

5 0
3 years ago
- 4(x – 4) – 3 = 12 + 6x
BlackZzzverrR [31]

answer:

1/10 as a fraction or if you want it as a decimal it would be 0.1

step-by-step explanation:

-4(x-4)- 3=12+6x after seeing you multiply -4 by x and -4

and you would get

-4x+0-3=12+6x and then you distribute all the way and you would get

1/10 or if you dont want a fraction and want a decimal is would be 0.1

8 0
3 years ago
Read 2 more answers
If the set U = {all positive integers} and set A = {x|x ∈ U and x is an odd positive integer}, which describes the complement of
dlinn [17]

Answer: Choice D) set of even integers

=======================================================

Explanation:

U = universal set = {all positive integers} = {1, 2, 3, 4, 5, ...}

A = {stuff in set U that is odd} = {1, 3, 5, 7, 9, ...}

A^c = {stuff in set U but NOT from set A} = {2, 4, 6, 8, ...}

A^c = {set of even numbers from set U}

In set theory, the complement is simply the complete opposite. If the number 7 is found in set A for instance, then 7 is not going to live in the complement A^c

The opposite of the odd numbers is the set of even numbers.

Therefore, we go for <u>choice D</u> as our final answer.

Side note: if we union set A with its complement A^c then we get the universal set as a result. A \cup A^c = \text{universal set} = \text{set of all positive integers}

5 0
3 years ago
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