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3 years ago

This is (compound) probability: Picking two numbers from 1-10 and getting a multiple of 3 both times.

Mathematics

1 answer:

NemiM [27]3 years ago

7 0

Answer:

There are 10 counters in the bag and you want the 4

As their is only one for the probability is

1/10

There are now 9 counters left in the bag.

You only want the even ones , which are 2 6 8 and 10 ( four has been taken out)

There are only four even counters in the bag of nine counters so the probability is

4/9

As you want both of these to occur, you need to multiply them

1/10 x 4/9 = 49/90

Step-by-step explanation:

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If tan theta = 10/13 and cos theta > 0 then sin2theta is what ?

svetoff [14.1K]

$sin2\alpha = \frac{260}{269}$

<u>Step-by-step explanation:</u>

We have , $Tan\alpha = \frac{Perpendicular}{Base} = \frac{10}{13}$ ,

We know that $sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }$

Substituting values of P & B , $sin\alpha = \frac{10}{\sqrt{10^{2} + 13^{2}} } = \frac{10}{\sqrt{269} }$

Now , $sin2\alpha = 2sin\alpha cos\alpha = 2sin\alpha \sqrt{1 - (sin\alpha)^{2} }$

⇒ $sin2\alpha =$ $\frac{10}{\sqrt{269} }$ × $\sqrt{1 - (\frac{10}{\sqrt{269} })^{2} }$ ×2

⇒ $sin2\alpha = \frac{20}{\sqrt{269} }( \sqrt{\frac{269 - 100}{269} } )$

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⇒ $sin2\alpha = \frac{260}{269}$

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3 years ago

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Hope someone can help me with this

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