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murzikaleks [220]
3 years ago
8

Using the statement, write an equation in one variable.

Mathematics
1 answer:
sattari [20]3 years ago
5 0

Answer:

n + (n + 1) + (n + 2) = 12 + 2(n + 2)

Step-by-step explanation:

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Quadrilateral JKLM is graphed with vertices at J(-2,2), K(-1,-5), L(4,0), and M(3,7).
AveGali [126]

Answer:

<u>Question (a)</u>

Midpoint of a line segment:

M=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Given:

  • J = (-2, 2)
  • L = (4, 0)

\implies \textsf{midpoint of }JL=\left(\dfrac{-2+4}{2},\dfrac{2+0}{2}\right)=(1,1)

Given:

  • M = (3, 7)
  • K = (-1, -5)

\implies \textsf{midpoint of }MK=\left(\dfrac{3-1}{2},\dfrac{7-5}{2}\right)=(1, 1)

<u>Question (b)</u>

Find slopes (gradients) of JL and MK then compare.  If the product of the slopes of JL and MK equal -1, then JL and MK are perpendicular.

\textsf{slope }m=\dfrac{y_2-y_1}{x_2-x_1}

Given:

  • J = (-2, 2)
  • L = (4, 0)

\implies \textsf{slope of }JL=\dfrac{0-2}{4+2}=-\dfrac13

Given:

  • M = (3, 7)
  • K = (-1, -5)

\implies \textsf{slope of }MK=\dfrac{-5-7}{-1-3}=3

\textsf{slope of }JL \times \textsf{slope of }MK=-\dfrac13 \times3=-1

Hence segments JL and MK are perpendicular

4 0
2 years ago
We need a step by step answer to 2(3 d-1)
Effectus [21]
First figure out what it mean
7 0
3 years ago
VERY URGENT PLEASE HELP!!!!!!!
Fittoniya [83]

Answer:

multiply 8 by 5 then round :D

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve for z. z³ = 64 Enter your answer in the box. z =
zlopas [31]

Answer:

z³ = 64

z³=4³

since power is equal, base will be same

z=4

Step-by-step explanation:

6 0
3 years ago
How do I figure this one out?
Inessa [10]
9k2-12k+4

(k2-6k)+(-6k+4) factor out the 3k from 9k2 0 6k: 3k(k-2) factor out -2 from -6k +4n: -2 (3k-2) factor out common term (3k-2) = (3k-2 ) (3k-2) that equals (3k-2)2
5 0
3 years ago
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