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3 years ago

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Joshua's recipe for chili requires 2 3/4 pounds of beef. Sondra's recipe for chili requires 2 2/3 pounds of beef. Which of t

hese statements is true?

1 answer:

Lemur [1.5K]3 years ago

4 0

Answer:

Step-by-step explanation:

Your question isn't complete but let me help out based on the information given.

Joshua's recipe for chili requires 2 3/4 pounds of beef. Sondra's recipe for chili requires 2 2/3 pounds of beef.

The pounds of beef required by both of them will be:

= 2 3/4 + 2 2/3

= 2 9/12 + 2 8/12

= 4 17/12

= 4 + 1 5/12

= 5 5/12

The difference in the pounds of beef required by both of them will be:

= 2 3/4 - 2 2/3

= 2 9/12 - 2 8/12

= 1/12

Also, we.can also infer that Joshua recipe for chili requires more pounds of beef than that of Sondra

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Which is bigger 2/5 or 4/9

Jlenok [28]

The easiest way to solve this comparison without any unusual comparisons is to find a common denominator for the two fractions.

2/5 = 18/45
4/9 = 20/45

Since 20/45 is bigger than 18/45, we know that 4/9 is greater than 2/5

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3 years ago

Find a set of parametric equations for y= 5x + 11, given the parameter t= 2 – x

Sati [7]

Answer:

$x = 2-t$ and $y = -5\cdot t +21$

Step-by-step explanation:

Given that $y = 5\cdot x + 11$ and $t = 2-x$ , the parametric equations are obtained by algebraic means:

1) $t = 2-x$ Given

2) $y = 5\cdot x +11$ Given

3) $y = 5\cdot (x\cdot 1)+11$ Associative and modulative properties

4) $y = 5\cdot \left[(-1)^{-1} \cdot (-1)\right]\cdot x +11$ Existence of multiplicative inverse/Commutative property

5) $y = [5\cdot (-1)^{-1}]\cdot [(-1)\cdot x]+11$ Associative property

6) $y = -5\cdot (-x)+11$ $\frac{a}{-b} = -\frac{a}{b}$ / $(-1)\cdot a = -a$

7) $y = -5\cdot (-x+0)+11$ Modulative property

8) $y = -5\cdot [-x + 2 + (-2)]+11$ Existence of additive inverse

9) $y = -5 \cdot [(2-x)+(-2)]+11$ Associative and commutative properties

10) $y = (-5)\cdot (2-x) + (-5)\cdot (-2) +11$ Distributive property

11) $y = (-5)\cdot (2-x) +21$ $(-a)\cdot (-b) = a\cdot b$

12) $y = (-5)\cdot t +21$ By 1)

13) $y = -5\cdot t +21$ $(-a)\cdot b = -a \cdot b$ /Result

14) $t+x = (2-x)+x$ Compatibility with addition

15) $t +(-t) +x = (2-x)+x +(-t)$ Compatibility with addition

16) $[t+(-t)]+x= 2 + [x+(-x)]+(-t)$ Associative property

17) $0+x = (2 + 0) +(-t)$ Associative property

18) $x = 2-t$ Associative and commutative properties/Definition of subtraction/Result

In consequence, the right answer is $x = 2-t$ and $y = -5\cdot t +21$ .

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3 years ago

P(X< ) 1-P(X> ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball

Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 30, p = 0.626$

So

$\mu = E(X) = np = 30*0.626 = 18.78$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65$

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is $P(X \leq 16 + 0.5) = P(X \leq 16.5)$ , which is the pvalue of Z when X = 16.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{16.5 - 18.78}{2.65}$

$Z = -0.86$

$Z = -0.86$ has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

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3 years ago

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galina1969 [7]

Answer:

Step-by-step explanation:

First, change the mixed numbers into improper fractions:

5 2/3 = 17/3

Then, find the common denominator:

41/6 + 17/3=

LCM = 6

17/3 *2 = 34/6

41/6 + 34/6

Last, Add

25/6 or

12 1/2

Hope this helps!

mark brainliest if possible!

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2 years ago

Wath is six hundred ninety- two thousand,four

ki77a [65]

692,004 is the answer

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3 years ago

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