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dusya [7]
3 years ago
13

Joshua's recipe for chili requires 2 3/4 ​ pounds of beef. Sondra's recipe for chili requires 2 2/3 ​ pounds of beef. Which of t

hese statements is true?
Mathematics
1 answer:
Lemur [1.5K]3 years ago
4 0

Answer:

Step-by-step explanation:

Your question isn't complete but let me help out based on the information given.

Joshua's recipe for chili requires 2 3/4 ​ pounds of beef. Sondra's recipe for chili requires 2 2/3 ​ pounds of beef.

The pounds of beef required by both of them will be:

= 2 3/4 + 2 2/3

= 2 9/12 + 2 8/12

= 4 17/12

= 4 + 1 5/12

= 5 5/12

The difference in the pounds of beef required by both of them will be:

= 2 3/4 - 2 2/3

= 2 9/12 - 2 8/12

= 1/12

Also, we.can also infer that Joshua recipe for chili requires more pounds of beef than that of Sondra

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Search cos jk and tan jk knowing that sin jk = 8/3
aleksley [76]

Answer:

cosjk = √55 i/3

tanjk = 8/√55 i

Step-by-step explanation:

Given

sin jk = 8/3

According to SOH CAH TOA

Sin theta = opposite/hypotenuse = 8/3

Opposite = 8

hypotenuse = 3

Get the adjacent using the pythagoras theorem

hyp² = opp²+adj²

adj² = hyp² - opp²

adj² = 3² - 8²

adj² = 9-64

adj² = -55

adj = √-55

adj = √55 i (i = √-1)

Get cosjk

cosjk = adj/hyp

cosjk = √55 i/3

Get tanjk

tanjk = opp/adj

tanjk = 8/√55 i

3 0
3 years ago
While shopping, Dawn finds a backpack that she likes on the sale rack. Its original price is $60,
Nadya [2.5K]

No. Because 33 $ is the money deducted from the 60 $. Dawn bought everything for less than 60 $.

So, if Dawn purchases everything on the rack with a 30% discount and 15% coupon the total will indeed make 45%.

We have to take 100% - 45%= 55% to know the reduction number. Let's proceed to the calculations now.

100%= 60 $

1%=60/100

55%= 60/100 × 55 = 33 $

Now <u>NOTE</u><u>;</u><u> </u><u>33</u><u> </u><u>$</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>money</u><u> </u><u>reduced</u><u> </u><u>from</u><u> </u><u>the</u><u> </u><u>60</u><u> </u><u>$</u><u>.</u><u> </u><u>So</u><u>,</u><u> </u><u>logically</u><u>,</u><u> </u><u>33</u><u> </u><u>$</u><u> </u><u>isn't</u><u> </u><u>the</u><u> </u><u>amount</u><u> </u><u>which</u><u> </u><u>Dawn</u><u> </u><u>purchased</u><u> </u><u>the</u><u> </u><u>whole</u><u> </u><u>rack</u><u>. </u>

To find the amount at which she purchased everything, we need to do,

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6 0
3 years ago
The estimated velocity v (in miles per hour) of a car at the end of a drag race is v=234 3√p/w (cube root) , where p is the hors
faltersainse [42]
Given that <span>v=234 3√p/w (cube root)
where </span><span> 
p is the horsepower of the car and
w is the weight (in pounds) of the car
v is the velocity in miles per hour

p = 1311 hp
w = 2744 lb
substitute the given value to the equation to solve for the velocity

v = 234 </span><span>3√(1311 / 2744)
v = 183 miles per hour is the velocity of a car at the end of a drag race.</span>
4 0
3 years ago
HURRY I NEED THIS BEFORE 12
I am Lyosha [343]
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5 0
3 years ago
3 people work full time together on a project, but their total time on the project is to be equivalent to only 1 person working
NikAS [45]
Let x = the amount of time that the third person needs to work on the job to add up to one

1 = 1/2 + 1/3 + x

1 - 1/2 - 1/3 = x

To subtract the fractions we need to put them all over a common denominator. Let's use 3*2 = 6 as the denominator; so 1 = 6/6, 1/2 = 3/6, 1/3 = 2/6:

6/6 - 3/6 - 2/6 = x

1/6 = x

The third person must work 1/6 time on the project.
3 0
3 years ago
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