Answer:
cosjk = √55 i/3
tanjk = 8/√55 i
Step-by-step explanation:
Given
sin jk = 8/3
According to SOH CAH TOA
Sin theta = opposite/hypotenuse = 8/3
Opposite = 8
hypotenuse = 3
Get the adjacent using the pythagoras theorem
hyp² = opp²+adj²
adj² = hyp² - opp²
adj² = 3² - 8²
adj² = 9-64
adj² = -55
adj = √-55
adj = √55 i (i = √-1)
Get cosjk
cosjk = adj/hyp
cosjk = √55 i/3
Get tanjk
tanjk = opp/adj
tanjk = 8/√55 i
No. Because 33 $ is the money deducted from the 60 $. Dawn bought everything for less than 60 $.
So, if Dawn purchases everything on the rack with a 30% discount and 15% coupon the total will indeed make 45%.
We have to take 100% - 45%= 55% to know the reduction number. Let's proceed to the calculations now.
100%= 60 $
1%=60/100
55%= 60/100 × 55 = 33 $
Now <u>NOTE</u><u>;</u><u> </u><u>33</u><u> </u><u>$</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>money</u><u> </u><u>reduced</u><u> </u><u>from</u><u> </u><u>the</u><u> </u><u>60</u><u> </u><u>$</u><u>.</u><u> </u><u>So</u><u>,</u><u> </u><u>logically</u><u>,</u><u> </u><u>33</u><u> </u><u>$</u><u> </u><u>isn't</u><u> </u><u>the</u><u> </u><u>amount</u><u> </u><u>which</u><u> </u><u>Dawn</u><u> </u><u>purchased</u><u> </u><u>the</u><u> </u><u>whole</u><u> </u><u>rack</u><u>. </u>
To find the amount at which she purchased everything, we need to do,
60 $ - 33 $ = 27 $
Given that <span>v=234 3√p/w (cube root)
where </span><span>
p is the horsepower of the car and
w is the weight (in pounds) of the car
v is the velocity in miles per hour
p = 1311 hp
w = 2744 lb
substitute the given value to the equation to solve for the velocity
v = 234 </span><span>3√(1311 / 2744)
v = 183 miles per hour is the velocity of a car at the end of a drag race.</span>
X=8 because add 11 to both sides and it becomes 28=3.5x and divide both sides by 3.5 so x=8
Let x = the amount of time that the third person needs to work on the job to add up to one
1 = 1/2 + 1/3 + x
1 - 1/2 - 1/3 = x
To subtract the fractions we need to put them all over a common denominator. Let's use 3*2 = 6 as the denominator; so 1 = 6/6, 1/2 = 3/6, 1/3 = 2/6:
6/6 - 3/6 - 2/6 = x
1/6 = x
The third person must work 1/6 time on the project.