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AlexFokin [52]
3 years ago
10

Aaron bought 16 identical bags of candy for a party. He gave the cashier $40 and was given $0.96 in change. How much did Aaron p

ay for one bag of candy?
Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

$2.44

Step-by-step explanation:

By taking away the change, you get the total being $39.04. Dividing that by 16 gets you the cost of one bag.

16x + 0.96 = 40

x = 2.44

Lera25 [3.4K]3 years ago
5 0

Answer:

$2.44

Step-by-step explanation:

Each bag cost $2.44

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Answer:

  c = 1.45

Step-by-step explanation:

Solving the equation for c, we find ...

  p +e = nc

  c = (p +e)/n

Filling in the values given, we have ...

  c = (4050 +300)/3000 = 4350/3000 = 1.45

The value of c is 1.45.

5 0
3 years ago
Answer correctly plz first and that is correct will get brainliest.
Zanzabum

Answer:

The bag of chips and the pretzel are 14.

The cookie is 8.

The popcorn is 13.

"?" is 222.

Step-by-step explanation:

We know that the bag of chips and the pretzel are equal to each other so all we have to do to figure them out is to divide 42 by 3, which gets us 14.

So, now we know the bag of chips and the pretzel are both 14.

To figure out what the cookie is, we take 14 away from 30, which gets us 16. Two cookies are 16 which means that one cookie is 8.

To figure out what the popcorn is, we have to take away 16 from 29 since two cookies are 16. 29 minus 16 is 13.

Popcorn therefore is 13.

Two popcorns' is 26.

26 multiplied by 8 is 208.

208 plus 14 is 222.

Hope that made sense and answered your question! :)

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3 years ago
Question 6
pishuonlain [190]

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