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AlexFokin [52]
3 years ago
10

Aaron bought 16 identical bags of candy for a party. He gave the cashier $40 and was given $0.96 in change. How much did Aaron p

ay for one bag of candy?
Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

$2.44

Step-by-step explanation:

By taking away the change, you get the total being $39.04. Dividing that by 16 gets you the cost of one bag.

16x + 0.96 = 40

x = 2.44

Lera25 [3.4K]3 years ago
5 0

Answer:

$2.44

Step-by-step explanation:

Each bag cost $2.44

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Graph the image of Kite BCDE after a translation 5 units down.​
NeTakaya

Answer:

See attachment for the translated kite

<em></em>

Step-by-step explanation:

Given

The attached image of BCDE

Required

Translate 5 units down

From the attachment;

B = (-7,0)

C = (0,5)

D =(-7,10)

E = (-10,5)

The rule to translate 5 units down is:

(x,y) \to (x,y-5)

So:

B' = (-7,-5)

C' = (0,0)

D' = (-7,5)

E' = (-10,0)

<em>See attachment for the translated kite</em>

3 0
2 years ago
Mr Patel is planning to drive 325 miles. He will stop one hour for lunch and take a 15 min rest break.
mr_godi [17]

Option D

The trip lasts for 6\frac{1}{4}\ hours

<em><u>Solution:</u></em>

<em><u>Mr Patel is planning to drive 325 miles</u></em>

Average speed is 65 mph

He will stop one hour for lunch and take a 15 min rest break

Let us first find the time taken

Time = \frac{distance}{speed}

Time = \frac{325}{65}\\\\Time = 5

Thus he covers 325 miles in 5 hours

Also, given that, he will stop one hour for lunch and take a 15 min rest break

<em><u>Therefore, total time taken for trip is:</u></em>

Total time = 5 hours + 1 hour + 15 minutes

Total time = 6 hours 15 minutes

We know that,

1 hour = 60 minutes

Therefore,

6\ hours\ 15\ minutes\ = 6 + \frac{15}{60}\ hours = 6 + \frac{1}{4} = 6\frac{1}{4}\ hours

Thus the trip lasts for 6\frac{1}{4}\ hours

8 0
3 years ago
B. Solve the following Polynomials:<br>1. u³ + 64​
Art [367]

Answer:

(4 + u)(16 – 4u + u2)

Step-by-step explanation:

64 + u3.

= 43 + u3.

= (4 + u)(42 – 4.u + u2).

= (4 + u)(16 – 4u + u2).

3 0
3 years ago
The median household incomes in dollars in four towns over time are shown. Assume the median incomes increase linearly. Median H
marysya [2.9K]

Answer:

Step-by-step explanation:

Household.          Year 2010.         Year 2015.           Difference

Adderley.              47,200               58,200.                11,000

Bonniville.              52,900.             62,400.                9,500

Clay City.               44,600.              57,600.                13,000

Daletown.              41,500.               54,000.               12,500

Percentage increase for Adderley = 11,000/47,200 * 100= 23.3%

Percentage increase for Bonniville = 9,500/52,900 * 100= 17.96%

Percentage increase for Clay City = 13,000/44,600 * 100= 29.15%

Percentage increase for Daletown = 12,500/41,500 * 100= 30.12%

We can now see that Bonniville is the city with the lowest rate of increase in median household income.

7 0
3 years ago
To​ ​ get​ ​ an​ ​ accurate​ ​ result,​ ​ a​ ​ sample​ ​ size​ ​ must​ ​ be
levacccp [35]
At least 30 ..................
8 0
3 years ago
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