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Romashka-Z-Leto [24]
3 years ago
7

I need help if you help me I give you point

Mathematics
2 answers:
rusak2 [61]3 years ago
8 0

Any number with 3 in the tens place.

So, B.

wel3 years ago
7 0

Answer:

Step-by-step explanation:

hope that helps

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The density of silver (Ag) is 10.5 g/cm3. Find the mass of Ag that occupies 965 cm3 of space.
Luda [366]

Answer:

<h3>The answer is 10132.5 g</h3>

Step-by-step explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of silver = 965 cm³

density = 10.5 g/cm³

The mass of silver is

mass = 965 × 10.5

We have the final answer as

<h3>10132.5 g</h3>

Hope this helps you

5 0
4 years ago
Help me with this worth 10 points
nasty-shy [4]
I would choose D and C

Hope this Helps!!!!
7 0
3 years ago
Read 2 more answers
An integer n between 1 and 99, inclusive, is to be chosen at random.
Oxana [17]
The answer would be D :)
5 0
3 years ago
Evaluate - 2x + y6x<br> When x = 1, y = -5
mojhsa [17]

Answer:

-28

Step-by-step explanation:

2(1) + (-5)6(1)

2+-30

-28

6 0
3 years ago
What are the correct answers and why? Simple and concise explanation please!!!
dezoksy [38]

Answer:

\large\boxed{-\bigg[(x-3)^2+2x\bigg]+1}\\\\\boxed{-x^2+4x-8}

Step-by-step explanation:

(g\ \circ\ f)(x)=g\bigg(f(x)\bigg)

f(x)=(x-3)^2+2x\\\\g(x)=-x+1\\\\g\ \circ\ f\to\text{put f(x) instead of x in the function g(x)}:\\\\(g\ \circ\ f)(x)=-\bigg[\underbrace{(x-3)^2+2x}_{x}\bigg]+1

-----------------------------------------

-\bigg[(x-3)^2+2x\bigg]+1=-(x-3)^2-2x+1\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=-(x^2-(2)(x)(3)+3^2)-2x+1=-(x^2-6x+9)-2x+1\\\\=-x^2-(-6x)-9-2x+1=-x^2+6x-9-2x+1\\\\\text{combine like terms}\\\\=-x^2+(6x-2x)+(-9+1)=-x^2+4x-8

-----------------------------------

-x^2+4x-8=-x^2+4x-2^2+2^2-8=-(x^2-4x+2^2)+4-8\\\\=-(\underbrace{x^2-(2)(x)(2)+2^2}_{(a-b)^2=a^2-2ab+b^2})-4=-(x-2)^2-4=-(x+1-3)^2-4

In\ (-x+1-3)^2+2x,\ x^2\ will\ be\ positive.\\In\ (-x+1-3)^2+2(-x+1),\ x^2\ will\ be\ positive.

6 0
3 years ago
Read 2 more answers
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