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igor_vitrenko [27]
3 years ago
11

I need help with this plz and thank you

Mathematics
1 answer:
fgiga [73]3 years ago
6 0

Answer:

The answer is: w  =  − 30

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aleksandr82 [10.1K]

We know that According to Algebra of Real Functions :  

If f and g are two real functions which are defined under the same domain then (\frac{f}{g})(x) = \frac{f(x)}{g(x)}

\implies Given\;Function\;is\;\frac{-1}{x\sqrt{3x - 9}}

Now we need find the Domain of this Function :

The Condition for Square Root to be defined is any Expression under it should be Greater than or Equal to Zero.

When Function is a Fraction, it Cannot be defined when the denominator becomes zero. Because when the denominator is zero, the fraction tends to ∞ (because anything divided by zero tends to ∞)

According to Above Conditions Described above, The Given Function is Definable only when the Expression which is under the Square Root is Greater than Zero and x ≠ 0

⇒ 3x - 9 > 0

⇒ 3x > 9

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⇒ The Domain of the Given Function is (3 , ∞)

1st Option is the Answer

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4 years ago
What is the result when 6x^3+13x^2+27x+14 is divided by 3x+2
aliya0001 [1]
6x^3+13x^2+16 is the result.
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Jesus Christ had dreads so shake em', I ain't got none but I'm planning on growing some​
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