This problem Is an example of geometrica progression. The formula
for the sum of geometric progression is:
S = a[(r^n)-1] / (r – 1)
Where s is the sum
a is the first term = 1
r is the common ratio = 2 ( because it doubles every year
n is the number of terms = (19) since the first term is when
he was born which he still 0
s = S = 1[(2^19)-1] / (2 – 1)
s = $524,287
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Answer:
B
Step-by-step explanation:
Stopping at a stoplight means that Chris's speed would be zero on the graph. The times that his speed is zero are times t = 0, t = 2 min, t = 11 min, and t = 21 min. Because the graph shows his speed from the time he left his house (at t = 0) to the time he arrived at the theater (at t = 21 min), the most likely times he stopped at stoplights are times t = 2 min and t = 11 min.
Step-by-step explanation:
mcdonalds..........01.
