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aleksley [76]
3 years ago
5

Which of the following statements can be used to show that today's high temperature, 12°F, is warmer than yesterday's high tempe

rature, which was -15°F?
-15°F = 12°F
-15°F ≥ 12°F
-15°F 72°F
Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0

Answer:

-15°F < 12°F

Step-by-step explanation:

Hope it helps you in your learning process.

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Please help me now plz I will mark you brainliest
PIT_PIT [208]

Answer:

On the circle

Step-by-step explanation:

Because all of the points on a circle are equidistant from the center, if a circle has a radius of 10 then all of the points are 10 units from the center. Using the Pythagorean Theorem, you know that the distance from (4,0) to (-2,8) is:

\sqrt{(4-(-2))^2+(8-0)^2}=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10, meaning that it is on the circle. Hope this helps!

7 0
3 years ago
The Miller family visited Mama's Kitchen and ordered 4 hamburgers and 3 medium fries and paid $17.35. James ordered a medium dri
Airida [17]
Know: 17.35 is equivalent to 4 burgers 3 med fries
6.09 Is equivalent to 1 burger med fries
9.34 8s equivalent to 2 burgers med fries and med drink
So what you want to do is take 6.09 and subtract it from 9.34 which is 3.25. Now 3.25 is your burger price.
What you want to do now is take your 3.25 and multiply it by 4 which would be 13. 17.35 subtract 13 would be 4.
4 divided by 3 is 1.33 which is now the price of a med fries.
now for the drink. 3.25 plus 1.33 is 4.58.
6.09 subtract 4.58 is 1.51
Now you have 3.25 as your burger
1.33 as your fries
1.52 for your drink
6 0
3 years ago
Please help? I dont understand how to do this
vodomira [7]
(3x+4)(x+6) is the answer
8 0
3 years ago
Correct each of the following errors 4a^2x3a^5=(4+3)a^2+5=7a^7
Bogdan [553]

Answer:

the left hand side dose not equale 7a^7

Step-by-step explanation:

4a^2x3a^5=7a^2+5=7a^7

16ax3a^5=7a^7=7a^7

48a^5=7a^2+5=7a^7

3 0
3 years ago
Name:
Marysya12 [62]

Answer:

200 rev.

Step-by-step explanation:

0.7*\pi=\frac{11}{5} \\\\440÷\frac{11}{5} = 200

4 0
3 years ago
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