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3 years ago

If someone would help me that would be amazing

Mathematics

1 answer:

olchik [2.2K]3 years ago

5 0

Given:
(x₁,y₁) = (-2,4)
(x₂,y₂) = (0,2)

Determine the slope of the function
m = (y₂ - y₁) / (x₂ - x₁)
m = (2 - 4) / (0 + 2)
m = -2/2
m = -1

Determine the equation
y - y₁ = m(x - x₁)
y - 4 = -1(x - (-2))
y - 4 = -1 (x + 2)
y - 4 = -x - 2
y = -x - 2 + 4
y = -x + 2
f(x) = -x + 2

The correct answer is first option

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Need to find volume, step by step explanation pls <br><br><br><br>

worty [1.4K]

Given:

A figure of combination of hemisphere, cylinder and cone.

Radius of hemisphere, cylinder and cone = 6 units.

Height of cylinder = 12 units

Slant height of cone = 10 units.

To find:

The volume of the given figure.

Solution:

Volume of hemisphere is:

$V_1=\dfrac{2}{3}\pi r^3$

Where, r is the radius of the hemisphere.

$V_1=\dfrac{2}{3}(3.14)(6)^3$

$V_1=\dfrac{6.28}{3}(216)$

$V_1=452.16$

Volume of cylinder is:

$V_2=\pi r^2h$

Where, r is the radius of the cylinder and h is the height of the cylinder.

$V_2=(3.14)(6)^2(12)$

$V_2=(3.14)(36)(12)$

$V_2=1356.48$

We know that,

$l^2=r^2+h^2$ [Pythagoras theorem]

Where, l is length, r is the radius and h is the height of the cone.

$(10)^2=(6)^2+h^2$

$100-36=h^2$

$\sqrt{64}=h$

$8=h$

Volume of cone is:

$V_3=\dfrac{1}{3}\pi r^2h$

Where, r is the radius of the cone and h is the height of the cone.

$V_3=\dfrac{1}{3}(3.14)(6)^2(8)$

$V_3=\dfrac{25.12}{3}(36)$

$V_3=301.44$

Now, the volume of the combined figure is:

$V=V_1+V_2+V_3$

$V=452.16+1356.48+301.44$

$V=2110.08$

Therefore, the volume of the given figure is 2110.08 cubic units.

7 0

2 years ago

Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n

Svetradugi [14.3K]

Complete Question

Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150

Answer:

Normal sampling distribution can not be used

Step-by-step explanation:

From the question we are told that

The null hypothesis is $H_o : p = 0.015$

The alternative hypothesis is $H_a : p < 0.015$

The sample size is n= 150

Generally in order to use normal sampling distribution

The value $np \ge 5$

$np = 0.015 * 150$

$np = 2.25$

Given that $np < 5$ normal sampling distribution can not be used

8 0

3 years ago

Data consistent with summary quantities in the article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among

Olegator [25]

Answer:

a) X[bar]₁= 1839.20 cal

b) X[bar]₂= 1779.07 cal

c) S₁= 386.35 cal

Step-by-step explanation:

Hello!

You have two independent samples,

Sample 1: n₁= 15 children that did not eat fast food.

Sample 2: n₂= 15 children that ate fast food.

The study variables are:

X₁: Calorie consumption of a kid that does not eat fast food in one day.

X₂: Calorie consumprion of a kid that eats fast food in one day.

The point estimate of the population mean is the sample mean

X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal

X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal

To calculate the sample standard deiation, you have to calculate the sample variance first:

S₁²= $\frac{1}{n_1-1}$ [∑X₁² - (( ∑X₁)²/n₁)]= $\frac{1}{14} + [52829538 - (\frac{27588^{2} }{15})$ = 149263.4571 cal²

S₁= 386.35 cal

I hope it helps!

7 0

2 years ago

There are 12 chocolate chip cookies in an assortment of 48 cookies. What percent of the cookies are chocolate chip?

Annette [7]

Answer: 20 Chocolate Chips

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Help me on this problem

Wittaler [7]

Answer:

1 and 3 are both perpendicular to segment NY

Step-by-step explanation:

1. Find the slope of line NY

slope of NY = 5-(-7)/-11-5 = - 3/4

Any line that is perpendicular to NY should have a slope of the inverse of negative slope of NY.

2.Find the slope of perpendicular lines

the inverse of negative slope of NY = - (-4/3) = 4/3

3 0

3 years ago