The mistake CJ likely made is multiplying using the reciprocal of -3/4. The correct option is d. He multiplied using the reciprocal of -3/4

From the question,

We are to determine the correct quotient.

The given division operation to be carried out is -3/4 divided by 1/4

The correct quotient can be determined as shown below

$-\frac{3}{4} \div \frac{1}{4}$

Multiply $-\frac{3}{4}$ by the reciprocal of $\frac{1}{4}$

The reciprocal of $\frac{1}{4}$ is $\frac{4}{1}$

Then, we get

$-\frac{3}{4} \times \frac{4}{1}$

This gives

$-\frac{12}{4}$

= -3

The correct quotient is -3

The mistake CJ likely made is multiplying using the reciprocal of -3/4.

Hence, the correct quotient is -3

The mistake CJ likely made is He multiplied using the reciprocal of -3/4. The correct option is d. He multiplied using the reciprocal of -3/4

Learn more here: brainly.com/question/13124034

6 0

3 years ago

Anna, Gina, and Ted divided up a box of post cards. Anna took one-fourth of the cards. Gina took half of what remained. Ted took

aliina [53]

Answer:

16 cards

Step-by-step explanation:

We can use logic to find out how many cards were in the beginning.

If Ted took 6 cards, and Gina took half of what remained, then when Gina took cards, she had $6\cdot2=12$ to choose from.

Now, Anna took $\frac{1}{4}$ of the cards, meaning that 12 is $\frac{3}{4}$ of the amount of cards there originally were.

$\frac{12}{x} = \frac{3}{4}\\\\12\cdot4=48\\\\48\div3=16$

Hope this helped!

3 0

3 years ago

Read 2 more answers

Find the value of x and y in this problem.

Brut [27]

$\frac{x}{y}$ = - $\frac{3}{2}$

given

$\frac{x-y}{x+y}$ = 5 ( cross- multiply )

5(x + y) = x - y

5x + 5y = x - y ( subtract (x - y) from both sides )

4x + 6y = 0 ( subtract 6y from both sides )

4x = - 6y

$\frac{x}{y}$ = - $\frac{6}{4}$ = - $\frac{3}{2}$

8 0

3 years ago