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2 years ago

Plss help I’ll mark brainliest

Mathematics

2 answers:

melamori03 [73]2 years ago

4 0

Answer:

D 6

Step-by-step explanation:

Normally when I multiply mixed numbers, I change them to improper fractions first so that it is easier.

1 $\frac{2}{10}$ × 5 = $\frac{12}{10}$ × 5

Multiply 5 by the numerator of the fraction and leave the denominator alone.

$\frac{12}{10}$ × 5 = $\frac{60}{10}$

Change back to simplest form.

$\frac{60}{10}$ = 6

xz_007 [3.2K]2 years ago

3 0

Answer:

D. 6

Step-by-step explanation:

If you convert to a decimal it's easier to multiply

2/10 = 0.2

1.2 * 5 =6

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Which statements are true based on the diagram? Check all that apply.

GrogVix [38]

First statement: False. Points K, M and N form a triangle.
Second statement: True. Points J, K, and Q are on the same line.
Third statement: False. KN and MQ intersect at N, not at R.
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Fifth statement: True. By definition, there is always only 1 line that can be drawn between 2 given points.

6 0

3 years ago

Read 2 more answers

Evaluate 2/3+3/4 <br> 1and5/12

chubhunter [2.5K]

2/3 + 3/4 = 8/12 + 9/12 = 17/12 = 1 5/12

1 + 5/12 = 12/12 + 5/12 = 17/12 = 1 5/12

2/3 + 3/4 = 1 + 5/12

6 0

3 years ago

if a triangle is an equilateral triangle then the triangle has exactly three 60 angles abc is an equilateral triangle

Artist 52 [7]

Answer:

The statement is always TRUE

Step-by-step explanation:

An equilateral triangle has all angles and all sides equal

The sum of angles in a triangle is 180 degrees.

Let each of the angles be x degrees.

Then we solve the following equation for x.

$x+x+x=180\degree$

$\implies 3x=180$

$\implies x=\frac{180}{3}=60\degree$

7 0

3 years ago

g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o

natali 33 [55]

Answer:

The tangent line to the given curve at the given point is $y=9x-26$ .

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of $y=2x^2-7x+6$ and then evaluate it for $x=4$ .

$(y=2x^2-7x+6)'$ Differentiate the equation.

$(y)'=(2x^2-7x+6)'$ Differentiate both sides.

$y'=(2x^2)'-(7x)'+(6)'$ Sum/Difference rule applied: $(f(x)\pmg(x))'=f'(x)\pm g'(x)$

$y'=2(x^2)'-7(x)'+(6)'$ Constant multiple rule applied: $(cf)'=c(f)'$

$y'2(2x)-7(1)+(6)'$ Applied power rule: $(x^n)'=nx^{n-1}$

$y'=4x-7+0$ Simplifying and apply constant rule: $(c)'=0$

$y'=4x-7$ Simplify.

Evaluate y' for x=4:

$y'=4(4)-7$

$y'=16-7$

$y'=9$ is the slope of the tangent line.

Point slope form of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

Insert 9 for $m$ and (4,10) for $(x_1,y_1)$ :

$y-10=9(x-4)$

The intended form is $y=mx+b$ which means we are going need to distribute and solve for $y$ .

Distribute:

$y-10=9x-36$

Add 10 on both sides:

$y=9x-26$

The tangent line to the given curve at the given point is $y=9x-26$ .

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function $f(x)=2x^2-7x+6$ at $x=4$ (the slope of the tangent line at $x=4$ ):

$\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}$

$\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}$ We are given f(4)=10.

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

$2x^2-7x-4=(x-4)(2x+1)$

Let's check this with FOIL:

First: $x(2x)=2x^2$

Outer: $x(1)=x$

Inner: $(-4)(2x)=-8x$

Last: $-4(1)=-4$

---------------------------------Add!

$2x^2-7x-4$

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

$\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}$

$\lim_{x \rightarrow 4}(2x+1)$

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0

3 years ago

Find the parabola whose minimum is at (−12,−2)(−12,−2) rather than the point given in the book. the parabola's equation is y=x2+

Hoochie [10]

The vertex form of the equation of a parabola is given by

$y-k=a(x-h)^2$

where (h, k) is the vertex of the parabola.

Given that the vertex of the parabola is (-12, -2), the equation of the parabola is given by

$y-(-2)=a(x-(-12))^2 \\ \\ y+2=a(x+12)^2=a(x^2+24x+144)=ax^2+24ax+144a \\ \\ y=ax^2+24ax+114a-2 \\ \\ y=x^2+24x+ \frac{114a-2}{a}$

For a = 1,

$y=x^2+24x+112$

<span>The parabola whose minimum is at (−12,−2) is given by the equation $y=x^2+ax+b$ , where a = 24 and b = 112.</span>

8 0

3 years ago