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maw [93]
3 years ago
13

Find the fifth term of the binomial expansion. (x2+y5) ^8

Mathematics
1 answer:
OlgaM077 [116]3 years ago
6 0

Answer:

The fifth term of the binomial expansion

T_{5} = 70 x^{8} y^{20}

Step-by-step explanation:

<u><em>Step:1</em></u>

Given that the binomial expansion

     ( x² + y⁵ )⁸

we know that

T_{r+1} = n_{C_{r} } a^{r} x^{n-r} ...(i)

<u><em>Step:2</em></u>

put r = 4  

T_{4+1} = 8_{c_{4} } (x^{2} )^{4} (y^{5} )^{8-4}

T_{5} = 70 x^{8} y^{20}

<u><em>Final answer:</em></u>-

The fifth term of the binomial expansion

T_{5} = 70 x^{8} y^{20}

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