All categories

3 years ago

Pls help me and I will mark u as brainliest plssss help

Mathematics

1 answer:

julsineya [31]3 years ago

5 0

Answer:

$x = 120 \times \cos(45) - 0 = 120 \times 0.7 = 84 \\ y = 120 \times \sin(45) - 150 = 84 - 150 = 64$

You might be interested in

Larry says 5 × 900 is less than 5 × 9,000. Doni says 5 × 900 is greater than 5 × 9,000. Which statements about the two products

BartSMP [9]

Answer:

Larry's statement is correct

Step-by-step explanation:

Larry says 5 × 900 is less than 5 × 9,000.

Doni says 5 × 900 is greater than 5 × 9,000.

5 × 900 = 4500

5 × 9000 = 45,000

45,000 is greater than 4500 because the place value of 45,000 is tens thousands and 4500 is Thousands.

Hence, Larry's statement is correct.(Larry says 5 × 900 is less than 5 × 9,000.)

8 0

3 years ago

A person purchased two boxes of light bulbs for 90 dollars including shipping.

Crazy boy [7]

Answer: x=10

Step-by-step explanation: 7x10 =77. 90-77=13 which was shipping

4 0

3 years ago

Is 8.47 L greater than 10

Ivahew [28]

No no no 10 is greater if it's difficult to you, you can write 10,00 it depends where the comma is. If it was 84,7 it is greater than 10

4 0

3 years ago

A small plane took 3 hours to fly 960 km from Ottawa to Halifax with a tail wind. On the return trip, flying into the wind, the

Rina8888 [55]

Answer:

Wind speed: $\rm 40\; km \cdot h^{-1}$ .
Speed of the plane in still air: $\rm 320\; km \cdot h^{-1}$ .

Step-by-step explanation:

This problem involves two unknowns:

wind speed, and
speed of the plane in still air.

Let the speed of the wind be $x \rm \; km \cdot h^{-1}$ , and the speed of the plane in still air be $y\rm \; km \cdot h^{-1}$ . It takes at least two equations to find the exact solutions to a system of two variables.

Information in this question gives two equations:

It takes the plane three hours to travel $\rm 960\; km$ from Ottawa to with a tail wind (that is: at a ground speed of $x + y$ .)
It takes the plane four hours to travel $\rm 960\; km$ from Halifax back to Ottawa while flying into the wind (that is: at a ground speed of $-x + y$ .)

Create a two-by-two system out of these two equations:

$\left\{ \begin{aligned}&3(x + y) = 960 && (1) \\ &4(-x + y) = 960 && (2) \end{aligned}\right.$ .

There can be many ways to solve this system. The approach below avoids multiplying large numbers as much as possible.

Note that this system is equivalent to

$\left\{ \begin{aligned}&4 \times 3 (x + y) = 4\times960 && 4 \times (1) \\ &3\times 4(-x + y) = 3\times 960 && 3 \times (2) \end{aligned}\right.$ .

$\left\{ \begin{aligned}&12 x + 12y = 4\times960 && 4 \times (1) \\ &- 12x + 12y = 3\times 960 && 3 \times (2) \end{aligned}\right.$ .

Either adding or subtracting the two equations will eliminate one of the variables. However, subtracting them gives only $1 \times 960$ on the right-hand side. In comparison, adding them will give $7 \times 960$ , which is much more complex to evaluate. Subtracting the second equation ( $3 \times (2)$ ) from the first ( $4 \times (1)$ ) will give the equation