Let s be Seth's age. let r be Romans age. 5 years ago Seth was s-5 and Roman was three times as old, or 3(s-5), or 3s-15=r-5
in ten years Seth will be s+10 and Roman will be twice as old, or 2(s+10), or 2s+20=r+10
3s-15 =r-5
r=3s-10
2s+20=r+10
r=2s+10
3s-10=2s+10
s=20
Seth is 20 years old
setting the two equations equal gives us
3(s-5)=2(s+10)
3s-15=2s+20
s=35
Answer:
11
Step-by-step explanation:
a = d1+d2 all divided by 2
7+7+4+4/2
14+8/2
22/2
11
Answer:
11
Step-by-step explanation:
(-3)²-3(-3)-7
9+9-7
11
Answer:
Answer: Janet is 16, and David is 11.
Step-by-step explanation:
Let the ages be j and d.
j = d + 5
j + d = 27
Substitute d + 5 for j in the second equation.
d + 5 + d = 27
2d + 5 = 27
2d = 22
d = 11
Substitute 11 for d in the first equation.
j = d + 5
j = 11 + 5
j = 16
Answer: Janet is 16, and David is 11.
