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White raven [17]
2 years ago
8

What can be visualized as a series of vertical lines around the Earth ​

Mathematics
2 answers:
Ilya [14]2 years ago
4 0

Answer:

roads?

Step-by-step explanation:

i think thats right

Morgarella [4.7K]2 years ago
4 0
Latitude lines are the lines. longitude lines are horizontal
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faust18 [17]
The correct like is C.
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3 years ago
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Help? Please?<br><br> Round the number to the thousandths place "79337.945573"
Ivan

\approx79337.946

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3 years ago
Nth term of this sequence 1, 10, 19, 28
mestny [16]

Answer:

The nth term of the sequence is

<h2>9n - 8</h2>

Step-by-step explanation:

The sequence above is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

From the question

a = 1

d = 10 - 1 = 9 or 19 - 10 = 9 or 28 - 19 = 9

So the nth term of the sequence is

A(n) = 1 + (n - 1)9

= 1 + 9n - 9

= 9n - 8

<h3>A(n) = 9n - 8</h3>

Hope this helps you

3 0
2 years ago
Which integer CANNOT be a solution to the inequality 6x − 4 ≤ 7x − 3 ?
mezya [45]

Answer:

0

Step-by-step explanation:

4 0
3 years ago
Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

Where the terms in f prime f^{1}(a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

f^{1}(a)=f^{1}(-4)=-8/(-4)^{2}

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+f^{1}(-4)(x+4)/1!+  f^{11}(-4)(x+4)^{2}/2!.............

=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+  24/(-4)^{3} (-4)(x+4)^{2}/2!.............

=-2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

3 0
11 months ago
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