To find the speed of the boats we will divide the distance by time.
From the graph we finde the boats' speeds as ;

And for the speed of the third boat, we will also divide the distance by time.

As you can see the speed of boat 3 (8 km/h) is more than boat 1 (7 km/h) and boat 2 (5 km/h).
Thus the third boat is faster than both of them.
The answer is B.
You can see the speed of boat 1 and 2 in the picture.
That would be one I guess
6(2 + 5t) = 6*2 + 6*5t = 12 + 30t
Answer is 12 +30t.
Answer:
1/4
Step-by-step explanation:
Favorable Outcomes/ All Possible Outcomes= 2/8
2/8= 1/4
The answer is 1/4.
Answer:
Let AB be the flagstaff and CD be the vertical tower.
AB=10m=EC
BC=20m=AE
In triangle ABC we have,
tanx=AB/BC
tanx=10/20
1/tanx=20/10
10/tanx=20...........1
In triangle ADE we have
tan(90-x)=DE/AE
cotx=DE/20
1/cotx=20/DE
DE/cotx=20..............2
by eq1 and. eq 2 we get
10/tanx=DE/cotx
10/(AB/BC)=DE/(BC/AB)
10/(10/20)=DE/(20/10)
10×20/10=DE×10/20
DE=40m
Therefore height of vertical tower = DE+EC=40+10=50m