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Cerrena [4.2K]
2 years ago
5

A store donated cases of crayons to a daycare center. Each case holds 24 boxes of crayons; each box holds 8 crayons. How many cr

ayons did the center receive?
Mathematics
2 answers:
lana [24]2 years ago
5 0

Answer:

I think its 192

Step-by-step explanation:

you just do 24 times 8

kakasveta [241]2 years ago
4 0

Answer:

192

Step-by-step explanation:

Just multiply 24 by 8.

I think thats it tho.

You might be interested in
Julian calculates the volume of a rectangular prism with the dimensions 3/4ft by 4 feet by 1/2 ft. His work is shown here.
lbvjy [14]

Answer:

He multiplied the denominators incorrectly

Step-by-step explanation:

we know that

The volume of a rectangular prism is given by the formula

V=LWH

we have

L=3/4 ft

W=5/1 ft

H=1/2

substitute

V=(3/4)(5/1)(1/2)= 3x5x1=    15

                           ₋₋₋₋₋₋₋₋    ₋₋₋₋ ft³

                           4x1x2=    8

                       

therefore

He multiplied the denominators incorrectly

7 0
2 years ago
Help pleaseeeeeee and good morning
dimulka [17.4K]

Answer:

1a w=-9                 1b s=20/7

2a x=12                 2b v=11

3a b=10                 3b a=9/5

4a c=1                    4b x=2

Step-by-step explanation:

6 0
3 years ago
Help!!!!!!!!! Please!!!!
Sedaia [141]

your answer is letter A,

6 0
3 years ago
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
The last question for my test help
alisha [4.7K]

3 2/6

5/6*4=20/6

20/6= 3 2/6 OR 3 1/3

8 0
3 years ago
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