Answer:
(A) 8y^2 +8y -10
(B) 22y^3 +2y^2 +2y -7
(C) yes, for these polynomials. The result of adding or subtracting the polynomials in this problem is another polynomial, suggesting the set of polynomials is closed to addition and subtraction.
Step-by-step explanation:
A. (4y + 2y^2 − 3) + (−4 + 2y^2 + 2y) + (4y^2 − 3 + 2y)
= y^2(2 +2 +4) +y(4 +2 +2) +(-3 -4 -3)
= 8y^2 +8y -10 . . . . total length of sides 1, 2, 3
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B. The length of the 4th side is the difference between the perimeter and the sum of the other three sides:
(22y^3 + 10y^2 + 10y − 17) -(8y^2 +8y -10)
= 22y^3 +y^2(10 -8) +y(10 -8) +(-17 +10)
= 22y^3 +2y^2 +2y -7 . . . . length of 4th side
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C. The result of adding or subtracting the polynomials in this problem is another polynomial, suggesting the set of polynomials is closed to addition and subtraction. An example is not a proof, but there is nothing about this example that would suggest a different conclusion.
The absolute value of -6 is the distance it is away from 0. The absolute value would be |-6| or |6| to show that the numeral is 6 spots away from 0.
G(x) = 3x
g(x) = 3*( x )
g(f(x)) = 3*( f(x) ) ... every x has been replaced with f(x)
g(f(x)) = 3*( 3x ) ... replace the f(x) on the right side with 3x
g(f(x)) = (3*3)x
g(f(x)) = 9x
The peasant had 28 hens and 42 rabbits
<h3>How to determine the number of hens and rabbits?</h3>
Represent hens with h, eggs with e and rabbits with r.
So, we have:
2r = 3h
e = 1/3h
Make h the subject in e = 1/3h
h = 3e
He got 72 pennies.
So, we have:
r + h = 72
Multiply through by 2
2r + 2h = 144
Substitute 2r = 3h in 2r + 2h = 144
3h + 2h = 144
Evaluate the sum
5h = 144
Divide by 5
h = 28.8
Remove decimal
h = 28
Recall that:
2r = 3h
So, we have:
2r= 3 * 28
Divide by 2
r = 3 * 14
Evaluate the product
r = 42
Hence, the peasant had 28 hens and 42 rabbits
Read more about equations at:
brainly.com/question/2972832
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Let her original savings be Y
Let money spent on furnitures be F
Let remaining savings be R