Answer:
![\text{1. }50^{\circ}\\\text{2. }80^{\circ}](https://tex.z-dn.net/?f=%5Ctext%7B1.%20%7D50%5E%7B%5Ccirc%7D%5C%5C%5Ctext%7B2.%20%7D80%5E%7B%5Ccirc%7D)
Step-by-step explanation:
1. The measure of an inscribed angle is always half the measure of the arc it forms. Since angle ACB forms arc AB with a measure of 100 degrees, the measure of angle ACB will be equal to
.
2. Relating to problem 1, both inscribed angles marked in the figure form the same arc. All inscribed angles forming the same arc will have the same measure. Therefore, the measure of angle GEF is equal to
.
First lets solve for x we know 3x=90. In this case x=30. Now we can solve for y. We know the triangle needs to equal 180 so y+2(30)=180. So we get y=120. Hope it helps
Answer:
![\frac{49}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B49%7D%7B4%7D)
Step-by-step explanation:
Convert each to a improper fraction
![3 \frac{2}{3} = \frac{11}{3}](https://tex.z-dn.net/?f=3%20%5Cfrac%7B2%7D%7B3%7D%20%3D%20%5Cfrac%7B11%7D%7B3%7D)
![8\frac{7}{12} = \frac{103}{12}](https://tex.z-dn.net/?f=8%5Cfrac%7B7%7D%7B12%7D%20%3D%20%5Cfrac%7B103%7D%7B12%7D)
![\frac{11}{3} +\frac{103}{12} = \frac{49}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B3%7D%20%2B%5Cfrac%7B103%7D%7B12%7D%20%3D%20%5Cfrac%7B49%7D%7B4%7D)
So I'm assuming the answers have to be the same?? if that's the case, 457×32=15904 so you would subtract 994 from 15904. That means the answer is 14,910. I hope this helped!
Answer:
Step-by-step explanation:
we have
![y=-2x^2+4x+3](https://tex.z-dn.net/?f=y%3D-2x%5E2%2B4x%2B3)
This is the equation of a vertical parabola open downward
The vertex represent a maximum
Convert the quadratic equation into vertex form
step 1
Factor -2
![y=-2(x^2-2x)+3](https://tex.z-dn.net/?f=y%3D-2%28x%5E2-2x%29%2B3)
step 2
Complete the square
![y=-2(x^2-2x+1)+3+2](https://tex.z-dn.net/?f=y%3D-2%28x%5E2-2x%2B1%29%2B3%2B2)
![y=-2(x^2-2x+1)+5](https://tex.z-dn.net/?f=y%3D-2%28x%5E2-2x%2B1%29%2B5)
step 3
Rewrite as perfect squares
----> equation in vertex form
The vertex is the point (1,5)