3 years ago

Who is single and lonely

Mathematics

2 answers:

Olegator [25]3 years ago

8 0

The answer to your question is me

Levart [38]3 years ago

8 0

Meeeeeeeeeeeeeeeeeeeeee

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Helpppp someone !!! It’s due midnight tonight .

postnew [5]

Answer:

Hey there,

Let the angle ABC = x

Let the angle CBE = y

Let the angle EBD = z

We want to find x.

So, we are given the following:

x+y+z=85

z=21

And y=z

therefore, both y and z must equal 21.

21+21=42

85-42=43.

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3 years ago

What is the area in polynomial form

rodikova [14]

Answer:

$\orange{ \boxed{ \sf{ ( \: {x}^{2} + 11x + 18 \: ) \: sq. \: units}}}$

Solution :

Area = lenght x width

Lenght = x + 9

Width = x + 2

$\sf \green{area \: = \: (x + 9)(x + 2)} \\ \sf \green{ = \: { {x}^{2} + 11x + 18}}$

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2 years ago

Write the integral and solve for the area under the curve:

ArbitrLikvidat [17]

Answer:

Integral: $\int\limits^\pi _0 {3sinx} \, dx$

Area: 6

Step-by-step explanation:

$\int\limits^\pi _0 {3sinx} \, dx = -3[cosx]_{0} ^{\pi} = 6$

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2 years ago

Which expression is equivalent to (5-2i)^2-i^3 where i^2=-1?

mr_godi [17]

$\text{use:}\\(a-b)^2=a^2-2ab+b^2\\\\(5-2i)^2=5^2-2\cdot5\cdot2i+(2i)^2=25-20i+2^2i^2\\\\=25-20i+4(-1)=25-20i-4=21-20i\\\\i^3=i^2\cdot i=(-1)i=-i$

$(5-2i)^2-i^3=21-20i-(-i)=21-20i+i=21-19i$

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4 years ago

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Musya8 [376]

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3 years ago